No one answer this I just wanna say hiiii

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

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MERRY CHRISTMASS!!! lets end the year by answering this math question

Andre45 [30]

Answer:

lol you didn't attach the question nut have a merry Christmas

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3 years ago

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What is 9- negative 7?

Dafna1 [17]

Nine subtracted from negative seven would be sixteen.

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3 years ago

Pamela is working during summer vacation to buy a $500 bike. If she works for 4 weeks and buys the bicycle, how much money will

dimaraw [331]

Answer:

Not enough information to solve

Step-by-step explanation:

In order to find the answer, you will need to know how much she makes in those 4 weeks, then subtract 500 from the total amount made

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3 years ago

7 3/9 - 2 4/9 =<br>11 3/4 - 5 1/4 =

jeka57 [31]

1.)

$7 \frac{3}{9} - 2 \frac{4}{9} \\ = \frac{66}{9} - \frac{22}{9} \\ = \frac{44}{9} \\ = 4 \frac{8}{9}$

2.)

$11 \frac{3}{4} - 5 \frac{1}{4} \\ = \frac{47}{4} - \frac{21}{4} \\ = \frac{26}{4} \\ = \frac{13}{2} \\ = 6 \frac{1}{2}$

<em>Hope it helps and is useful :)</em>

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3 years ago

In rectangle WXYZ, A is on side WX such that AX = 4, B is on side YZ such that BY = 18, and C is on side XY such that angle ACB=

Lemur [1.5K]

Answer:2*sqrt(130)

Step-by-step explanation: $From right triangle $AXC$, we have $\angle XAC = 90^\circ - \angle XCA$. We also must have $\angle YCB + \angle ACB + \angle XCA = 180^\circ$, so $\angle YCB = 180^\circ - 90^\circ - \angle XCA = 90^\circ - \angle XCA$, which means $\angle YCB = \angle XAC$. Combining this with $\angle X = \angle Y$, we have $\triangle XCA \sim \triangle YBC$ by AA Similarity, and\[\frac{CX}{AX} = \frac{BY}{CY},\]so\[\frac{CX}{4} = \frac{18}{2CX}.\]\\\\This gives us $2CX^2 = 72$, so $CX^2 =36$ and $CX=6$. \\\\\\\\$ $Therefore, $CY = 12$.Applying the Pythagorean Theorem to right triangles $XCA$ and $CYB$ gives us\begin{align*}CA^2 &= XA^2 + XC^2 = 16 + 36 = 52,\\BC^2 &= CY^2 + BY^2 = 144 + 324 = 468.\end{align*}Applying the Pythagorean Theorem to right triangle $ABC$ gives\[AB = \sqrt{AC^2 + BC^2} = \sqrt{52 + 468} = \sqrt{520} = \boxed{2\sqrt{130}}.\](We can also compute $AB$ by dropping a perpendicular from $A$ to $\overline{YZ}$, which creates a right triangle.)$

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3 years ago