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nikdorinn [45]
3 years ago
7

Find the length of the second leg of the triangle round to the nearest hundredth

Mathematics
1 answer:
horsena [70]3 years ago
7 0

Answer:

\displaystyle \frac{3\sqrt{230}}{5}

Step-by-step explanation:

Use the Pythagorean Theorem:

\displaystyle a^2 + b^2 = c^2 \\ \\ 9,7^2 + b^2 = 13,3^2; \sqrt{82,8} = \sqrt{b^2} \\ \\ \frac{3\sqrt{230}}{5}\:[or\:9,0994505329...] = b

So, you have this:

\displaystyle 9,1 ≈ b

I am joyous to assist you at any time.

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The length of a rectangle is the width minus 8 units. The area of the rectangle is 9 units. What is the length, in units, of the
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Length of rectangle is 1 unit  

<u>Solution: </u>

Given that  

Length of a rectangle is width minus 8 units.

Area of rectangle = 9 square units

Need to calculate the length of rectangle.

Let us assume width of rectangle = x

As Length is width minus 8,  

Length of the rectangle = x – 8

\text{ Area of rectangle }=\text{ width of rectangle }\times \text{ Length of the rectangle }

\text{ Area of rectangle }= x\times (x-8)

\text { Area of rectangle }=\left(x^{2}-8 x\right)

As given that area of rectangle = 9 square units

\begin{array}{l}{\Rightarrow x^{2}-8 x=9} \\\\ {\Rightarrow x^{2}-8 x-9=0}\end{array}

On solving above quadratic equation for x, we get

\begin{array}{l}{\Rightarrow x^{2}-9 x+x-9=0} \\\\ {\Rightarrow x(x-9)+1(x-9)=0} \\\\ {\Rightarrow (x-9)(x+1)=0}\end{array}

When x-9 =9, x = 9

When x + 1 = 0, x = -1

As width cannot be negative, so considering x = 9  

\text{ Length of rectangle }= x-8 = 9-8 = 1 \text{ unit }

Hence, Length of rectangle is 1 unit.

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