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melamori03 [73]
3 years ago
5

Plzzzzzzzzzzzzzzzzzzzz Help me with this question

Mathematics
2 answers:
Anon25 [30]3 years ago
7 0

Answer: 4 x 25 = 100

Step-by-step explanation:

Akimi4 [234]3 years ago
5 0
100 or the first one
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Evaluate |-3|<br><br> ±3<br> -3<br> 3
marin [14]

Answer:

Its just 3

Step-by-step explanation:

Because its absolute value.

Hope this helps!

4 0
3 years ago
Read 2 more answers
BAC ~ DEC what is the value of x?
Anna007 [38]

Answer: x = 37.8

Step-by-step explanation: We start with triangle ABC with two sides given as 15 and 18. We shall make angle C the reference angle and thereby calculate the third side, line BC.

Since we have the opposite side as 15, and the adjacent side (which lies between the reference angle and the right angle) as 18, we can use the tangent of the angle C

Tan C = Opp/Adj

Tan C = 15/18

Tan C = 0.8333

From our table of values/use of the calculator

Tan C = 39.8

Angle C in triangle ACB = Angle C in triangle ECD (Opposite angles are equal).

That takes us to triangle ECD, since the reference angle is known (39.8) and the opposite side is also given (31.5), we can now calculate the adjacent which is side x.

Tan C = Opp/Adj

Tan 39.8 = 31.5/x

when you cross multiply, x moves to the left hand side, while Tan 39.8 moves to the right hand side

x = 31.5/Tan 39.8

x = 31.5/0.8333

<u>x = 37.8</u>

5 0
3 years ago
I need help please thank you
aliya0001 [1]
\frac{ x^{2}-25 }{ x^{2}-3x-10 }
\frac{(x+5)(x-5)}{(x-5)(x+2)}
\frac{x-5}{x+2}

5 0
3 years ago
What is 23.5% as a Fraction? Will make brainliest btw :&gt;
Anastasy [175]

Answer:

23 1/2 or 47/2

Step-by-step explanation:

it just is

7 0
3 years ago
Read 2 more answers
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
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