So perimeter<u><</u>556
permiter=2Legnth+2Width
so perimiter=2(legnth+width)
556/2<u>></u>Legnth+width
228<u>></u>legnth +width
legnth =150
so 228<u>></u>150+width
subtract 150 from both sides
78<u>></u>width
width cand be 78 or less but not 0 or negative
anoth way to do it is 556<u>></u>2(150)+2width
556<u>></u>300+2width
subtract 300 from both sides
256<u>></u>2width
divide both sides by 2
78<u>></u>width
Of course for a rectangle A = L × W and we need to be careful about the units.
Here that's
18900 sq cm = L × 180 cm
where the area's in sq cm so we converted the width. We get
L = 18900 / 180 = 105 cm
We're asked for the result in meters, so that's
Answer: 1.05 m
The perimeter of the outer rectangle is
18.4 m + 32.5 m + 18.4 m + 32.5 m = 101.8 m
Answer: 101.8 m
The area of the seating space is the big rectangle minus the small rectangle,
A = 18.4(32.5) - 15(28) = 178 sq m
Answer: 178 sq m
