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3 years ago

Given g(t)=−3t+10, find (−3).

Mathematics

1 answer:

Lina20 [59]3 years ago

4 0

Answer:

the answer is 1

u have to substitute -3 in the question

that means t= -3

so, just do

3*-3+10

-9+10=1 hope it helps

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Point D is the incenter of triangle BCA. If m∠FDG = 136°, what is the measure of ∠FHG?

nikdorinn [45]

Given:

Point D is incenter of ΔBCA.

m∠FDG = 136°

To find:

The measure of ∠FHG

Solution:

Angle subtended by the arc at the center is twice that subtended on the remain part of the circle.

$\Rightarrow m\angle FDG = 2 m\angle FHG$

Divided by 2 on both sides.

$$\Rightarrow \frac{1}{2} m\angle FDG = \frac{1}{2} \times 2 m\angle FHG$

$$\Rightarrow \frac{1}{2} m\angle FDG = m\angle FHG$

Substitute m∠FDG = 136°

$$\Rightarrow \frac{1}{2} (136^\circ)= m\angle FHG$

$$\Rightarrow 68^\circ= m\angle FHG$

The measure of ∠FHG is 68°.

8 0

3 years ago

Read 2 more answers

Calculate the area of triangle ABC with altitude CD, given A(−7, −1), B(−1, 5), C(0, 0), and D(−3, 3). 9 square units 18 square

Kruka [31]

9514 1404 393

Answer:

18 square units

Step-by-step explanation:

Referring to the figure, we see that the base AB has a slope of 1, and the altitude CD has a slope of -1. The number of unit squares crossed by these segments are, respectively 6 and 3, so the length of each is ...

AB = 6√2

CD =3√2

The area is half the product of the base (AB) and height (CD) so is ...

A = 1/2bh = (1/2)(6√2)(3√2) = 18

The area of ΔABC is 18 square units.

_____

Additional comment

It is useful to remember that the diagonal of a unit square is √2. We used that fact here. If you need to figure it using the Pythagorean theorem, you find ...

c² = a² +b²

c = 1² +1² = 2

c = √2