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Papessa [141]
3 years ago
11

How to find the equation of vertical and horizontal asymptotes?

Mathematics
1 answer:
amm18123 years ago
5 0
Please find some specific examples of functions for which you want to find vert. or horiz. asy. and their equations.  This is a broad topic.

Very generally, vert. asy. connect only to rational functions; if the function becomes undef. at any particular x-value, that x-value, written as x = c, is the equation of one vertical asy.

Very generally, horiz. asy. pertain to the behavior of functions as x grows increasingly large (and so are often associated with rational functions).  To find them, we take limits of the functions, letting x grow large hypothetically, and see what happens to the function.  Very often you end up with the equation of a horiz. line, your horiz. asy., which the graph usually (but not always) does not cross.

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What is the converted metric unit for 75 cm
STALIN [3.7K]

Answer:

To inches?

Step-by-step explanation:

75 cm = is about like 30 inches

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Find the surface area of the following pyramid using its net. Please answer correctly the 4 questions and I'll give you brainlie
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The surface is 7.4344433322 acording to the exact dynamiter and angle of the pyrmaids

Step-by-step explanation

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How do I solve for y=160x+2=y=280x-3?
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Answer (5/264,76/33)
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Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
3 bags of chips cost 14.70 what is the price per bag
yawa3891 [41]

Answer:

4.90

Step-by-step explanation:

p/a=x

price/amount=x

14.70/3=4.90

7 0
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