Answer: D) No. The graph fails the vertical line test.
Explanation:
We are able to draw a single vertical line that passes through more than one point on the red curve. For example, we could draw a vertical line through x = 5 and have it cross the red curve at (5,4) and (5,-4).
So this is one example where the graph fails the vertical line test. It passes this test when such a thing doesn't happen. In other words, a function is only possible if any x input leads to exactly one and only one y output.
In this case, x = 5 leads to multiple outputs y = 4 and y = -4 at the same time. There are other x values which this occurs as well (any x values such that x > 1). So this is why we don't have a function.
Answer:
(5,2)
Step-by-step explanation:
You have to look to the X axis and you'll see the smiley face 5 bars/lines across from the vertex or 0.
Next, you'll need to look at the Y axis and see that the smiley face is 2 bars/lines vertically from 0.
So all you need to do is put the numbers into (x,y) and you'll get (5,2)
Hope this helps!
Answer: The answer is (d) 
Step-by-step explanation: Given equation to be factored is
The given expression is quadratic, so we can factor it into two linear factors, by using the following factorisation rule.
So, the given equation can be factorised using the above rule. The factorisation is as follows.
Thus, the correct option is (d).
Answer:
33/16
Step-by-step explanation:
x = y⁴/8 + 1/(4y²), 1 ≤ y ≤ 2
dx/dy = y³/2 − 1/(2y³)
Arc length is:
s = ∫ ds
s = ∫ √(1 + (dx/dy)²) dy
s = ∫₁² √(1 + (y³/2 − 1/(2y³))²) dy
s = ∫₁² √(1 + y⁶/4 − ½ + 1/(4y⁶)) dy
s = ∫₁² √(½ + y⁶/4 + 1/(4y⁶)) dy
s = ∫₁² ½ √(2 + y⁶ + 1/y⁶) dy
s = ∫₁² ½ √(y³ + 1/y³)² dy
s = ∫₁² ½ (y³ + 1/y³) dy
s = ½ (y⁴/4 − 1/(2y²)) |₁²
s = ½ (16/4 − 1/8) − ½ (1/4 − 1/2)
s = 33/16
Answer:
-3
Step-by-step explanation:
3x-1=-10
3x=-9
x=-3
