Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
The conditional probability illustrates that's there's a 2/8 that the event A occurs.
<h3>How to illustrate the probability?</h3>
It should be noted that probability simply means the likelihood of the occurence of an event.
In this case, it can be delivered that P(AID) and P(DIA) aren't equal.
Hence, P(D|A) has event A as its given event, resulting in 2/8 for a probability.
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It is <span>Round 0.172 to the nearest hundredth.</span>
Answer:
Step-by-step explanation:
AC = length of flagpole = 12 ft
AB = length of shadow = 14 ft
BC = length from the top of the flagpole to the end of the shadow = x ft
Use Pythagorean theorem to find the length of x,
x² = AC² + BC²
= 12² + 14²
= 144 + 196
= 340
x = √340
x = 18.4 ft
