Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)
One of them is real and the other two are complex conjugate roots
Since the real root is 4, then
x = 4
Since the complex root is (1 - i), then
The other root will be the conjugate of it (1 + i)
x = (1 - i)
x = (1 + i)
To find f(x) we will multiply the three factors of it
We can get the factors from the zeroes

Subtract 4 from both sides

The first factor is (x - 4)

The second factor is (x - 1 + i)
The third factor is (x - 1 - i)

We will multiply them to find f(x)

Multiply it by (x - 4)

The answer is
One important feature of the parabola is that it has an extreme point, called the vertex. If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function.
Answer:
B. y > 14
y which is students age is greater than 14