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mestny [16]
3 years ago
6

Scientists use indicator species as an early warning system for environmental problems. There are certain criteria that an indic

ator species must meet. They include ALL BUT ONE of those listed here. A) easily observable B) found at the base of any food chain C) not difficult to be sampled and/or counted D) sensitive to changes in environmental conditions
Physics
2 answers:
gtnhenbr [62]3 years ago
5 0

Answer:

definitely B

Explanation:

pshichka [43]3 years ago
4 0

The criteria of the indicator species that does not meet is:

<u>Found at the base of any food chain.</u>

<u>Option: B</u>

<u>Explanation:</u>

As an early warning system for environmental problems, indicator species are chosen for their sensitivity to environmental conditions. If the selected indicator species decrease in numbers or any health factor, it symbolizes to see for detrimental effects such as soil impurity, pollution in water/air, habitat fragmentation or drastic variation in climates.

Apart from being sensitive to change, these species must also be representative of the other organisms in the ecosystem, easily observable and must be sampled, and they should react continuously to environmental changes. So from the above conditions, it is clear that species found in any base of food chain is not the criteria.

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What is the maximum wavelength of incident light that can produce photoelectrons from silver? The work function for silver is Φ=
zalisa [80]

Answer:

4.24nm

0.385eV

Explanation:

Maximum wavelength (λmax) :

λmax = ( hc) /Φ

h = plancks constant = 6.63 * 10^-34

c = speed of light = 3*10^8

1ev = 1.6 * 10^-19

Φ = 2.93eV = 2.93* (1.6*10^-19) = 4.688*10^-19

λmax = [(6.63 * 10^-34) * (3 * 10^8)] / 4.688*10^-19

λmax = 19.89 * 10^-26 / 4.688*10^-19

λmax = 4.242 * 10^-7 m

λmax= 4.24nm

B.)

E = hc / eλ eV

λ = 3.75nm = 3.75 * 10^-7m = 375 *10^-9

E = (6.63 * 10^-34) * (3 * 10^8) / (1.6 * 10^-19) * (375 * 10^-9)

E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

E = 0.03315 * 10^2

E = 3.315 eV

Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

7 0
3 years ago
Each of the two coils has 320 turns. The average radius of the coil is 6 cm. The distance from the center of one coil to the ele
Temka [501]

Answer:

Magnetic field, B=2.39\times 10^{-3}\ T

Explanation:

It is given that,

Number of turns, N = 320

Radius of the coil, r = 6 cm = 0.06 m

The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m

Current flowing through the coils, I = 0.5 A

We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :

B=\dfrac{\mu_oINr^2}{(x^2+r^2)^{3/2}}

B=\dfrac{4\pi \times 10^{-7}\times 0.5\times 320\times (0.06)^2}{(0.03^2+0.06^2)^{3/2}}

B = 0.00239 T

or

B=2.39\times 10^{-3}\ T

So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is 2.39\times 10^{-3}\ T. Hence, this is the required solution.

7 0
4 years ago
Which property of matter is conserved in chemical reactions and shown by balanced equations?
bezimeni [28]

Answer:

Mass.

Explanation:

I took the quiz and got the answer right

8 0
2 years ago
Read 2 more answers
Choose the best description of the attraction between you and your classmate.
Lerok [7]

Answer:

The correct option is;

D. There is not enough information to answer this question

Explanation:

The universal gravitational constant = 6.67408 × 10⁻¹¹ 3³/(kg·s²)

For an in between distance of 1 m and equal masses of 60 kg, we have;

F = G \times \dfrac{m_{1}  \times m_{2}}{r^{2}} = 6.67408 \times 10^{-11}  \times \dfrac{60 \times 60}{1^{2}}  \approx  2.403 \times 10^{-7} N

The gravitational attraction ≈ 2.403 × 10⁻⁷ N, which does not correspond with the answers, therefore, the best option is that there is not enough information to answer this question.

5 0
3 years ago
Carbon and hydrogen are examples of pure substances or
Ede4ka [16]
The are elements on the periodic table
7 0
4 years ago
Read 2 more answers
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