What is the normal force in the image below?

At some point in an underground horizontal pipe, the speed of water is 2.5m/s and the gauge pressure is 2×104 Pa. What is the ga

lys-0071 [83]

The gauge pressure of the pipe is 2.234 ×10⁴ Pa, if the pipe is changed for another twice the area.

To find the gauge pressure the values given are,

speed of water = 2.5 m/s

Gauge pressure = 2×10⁴ Pa

<h3>What is pressure?</h3>

Definition:

Pressure can be defined as the total applied force per unit of area. The pressure depends both on externally applied force as well the area on which it is applied.

To find the gauge pressure first we have use continuity equation,

A ₁V₁ = A₂V₂

By the given condition: As the area is increased to twice the original area

A ₁V₁ = 2A₁V₂

A₁ gets cancelled on both the sides,

V₂ =V₁/2

=2.5 /2

V₂=1.25 m/s

Then, substituting the values in Bernoulli's equation,

Equation is given as,

P₁ + 1/2 ρV₁² = P₂ + 1/2 ρV₂²

Taking 1/2 ρ as common,

P₂ = 2×10⁴ + 1/2 ×1000×(2.5² -1.25²)

= 2×10⁴ + 2343.75

=22343.75 Pa

=2.234 ×10⁴ Pa

Thus, if the pipe is changed for another twice the area then the gauge pressure is 2.234 ×10⁴ Pa.

Learn more about pressure,

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6 0

1 year ago

A 3.53-g sample of aluminum completely reacts with oxygen to form 6.67 g of aluminum oxide. find percent composition

katrin2010 [14]

The mass percent composition of aluminum is 52.9% in aluminum oxide.

Mass of the aluminum = 3.53 g

Mass of the aluminum oxide = 6.67 g.

The mass percent of a substance is the mass of the substance divided by the mass of the compound into 100.

Aluminum reacts with oxygen to form aluminum oxide.

The overall balanced equation for the reaction is,

$Aluminum + Oxygen→Aluminum \: oxygen$

$4Al +3O _{2}→2Al _{2}O _{3}$

The mass percent composition of aluminum in the aluminum oxide is,

$Mass \: percent = \frac{ Mass \: of \: the \: substance}{ Mass \: of \: the \: compound} \times 100$

$Mass \: percent = \frac{Mass \: of \: the \: aluminum}{ Mass \: of \: the \: aluminum \: oxide } \times 100$

$Mass \: percent = \frac{3.53}{6.67 } \times 100$

= 52.9 %

Therefore, the mass percent composition of aluminum is 52.9% in aluminum oxide.

To know more about aluminum oxide, refer to the below link:

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7 0

1 year ago

1. In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the

shutvik [7]

Answer: 1. B. The number of electrons emitted from the metal per second increases.

2. The maximum speed of the emitted electrons increases.

The stopping potential increases

Explanation:

Photoelectric effect is simply referred to as the emission of electrons that occurs when there's an electromagnetic radiation. An example of such electromagnetic radiation is when material is being hit by light.

Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, the number of electrons emitted from the metal per second increases if the intensity of the incident light is increased.

Also, if the initial light incident on the metal surface causes electrons to be ejected from the metal, the maximum speed of the emitted electrons increases and the stopping potential increases.

4 0

2 years ago

What quickly forms on a cold glass on a hot day.

Zanzabum

Dew - small water drops, happens all the time, even to windows.

8 0

3 years ago

An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary

Talja [164]

Answer:

A) 5.2 x 10³ N

B) 8.8 x 10³ N

Explanation:

Part A)

$F_{g}$ = weight of the craft in downward direction = tension force in the cable when stationary = 7000 N

$T$ = Tension force in upward direction

$F_{d}$ = Drag force in upward direction = 1800 N

Force equation for the motion of craft is given as

$F_{g}$ - $F_{d}$ - $T$ = 0

7000 - 1800 - $T$ = 0

$T$ = 5200 N

$T$ = 5.2 x 10³ N

Part B)

$F_{g}$ = weight of the craft in downward direction = tension force in the cable when stationary = 7000 N

$T$ = Tension force in upward direction

$F_{d}$ = Drag force in downward direction = 1800 N

Force equation for the motion of craft is given as

$T$ - $F_{g}$ - $F_{d}$ = 0

$T$ - 7000 - 1800 = 0

$T$ = 8800 N

$T$ = 8.8 x 10³ N

4 0

3 years ago