Ask question

Ask question

All categories

4 years ago

12

-5m=4-6m I can't figure out the problem. I need help.

2 answers:

boyakko [2]4 years ago

8 0

-5m=4-6m: You would add -6m on both sides:
-5m=4-6m
+6m +6m And then you would get 1m=4 then divide both sides by 1 and you would get m=4

r-ruslan [8.4K]4 years ago

5 0

-5m = 4 - 6m....add 6m to both sides
6m - 5m = 4
m = 4 <==

You might be interested in

Someone plz help me with all of them

sukhopar [10]

15. They are still 6 blocks away from each other.
16. (-6,1) art and (-6,-2) animal. They are the same distance from each other as before because they moved together the same distance right to left across the coordinate plane.
17. The new location is (3,2). It is 8 blocks away from the old.

18.
A. I have attached the graph.
B. A triangle
C. $A= \frac{a*b}{2} = \frac{4*4}{2} = \frac{16}{2} =8 m^{2}$

Hope that helps

3 0

4 years ago

What is the value of the angle X in the following diagram ?

nikklg [1K]

Answer:

D

$x + 40 \degree = 180\degree \\ x = 180\degree - 40\degree \\ x = 140\degree$

7 0

3 years ago

Read 2 more answers

A botanist wishes to estimate the mean number of seeds for a certain fruit. She samples 11 specimens and finds the average numbe

Aliun [14]

Answer:

a)The 98% of confidence intervals are

Lower bound of CI = 47 -3.82436 = 43.1756

Upper bound of CI = 47 + 3.82436 = 50.8243

b) The conditions are required for the validity of the interval

A) μ known

Step-by-step explanation:

<u>Explanation</u>:-

The given sample size is 'n' =11

Given the average number of seeds is 47 with a standard deviation of 7

Sample mean (x⁻) = 47

Standard deviation (S) = 7

<u>The 98% of confidence intervals are</u>

$(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )$

$(47 - t_{0.02} \frac{7}{\sqrt{11} } , 47+ t_{0.02}\frac{7}{\sqrt{11} } )$

The degrees of freedom = n-1 =11-1 =10

t₀.₀₂= 1.812 ( from t - table)

now the intervals are

$(47 - 1.812 \frac{7}{\sqrt{11} } , 47+ 1.812\frac{7}{\sqrt{11} } )$

<u>Lower bound of CI = 47 -3.82436 = 43.1756</u>

<u>Upper bound of CI = 47 + 3.82436 = 50.8243</u>

The conditions are required for the validity of the interval

<u>A) μ known</u>

<u>Explanation</u>:-

If a random sample xi of size 'n' has been drawn from a normal population with a specified mean (μ) known.

The limit for (μ) is given by

$(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )$

5 0

3 years ago

Are similar to each other.<br> circles<br> polygons<br> rectangles<br> triangles

Ganezh [65]

What is the question though?

5 0

4 years ago

Read 2 more answers

What is the equation for the line? <br><br> (2,16) (1,8) (0,0) (-4,16)

shtirl [24]

Y=-8x count the differences between the x's and y's from each point. y-int is at 0

3 0

3 years ago