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Vanyuwa [196]
3 years ago
13

Find the perimeter....

Mathematics
1 answer:
8090 [49]3 years ago
4 0

The perimeter is adding all the outside edges together:

4 + 1 +4 +1 + 3 + 1 = 14 cm.

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HELP PLEASE ASAP!!!!
max2010maxim [7]
For the second question, the answer would be A because the lines intersect at 2 and -1.4. For the first question, t+b is less than or equal to 20 and 15b+8b is greater than or equal to 150 is the answer because Nick can work <u>up to </u>20 hours and needs to make <u>at least</u> $150 per week so that answer fits best. That question is solved mostly by context clues. 
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The sum of two numbers is 39. The larger number is 15 more than the smaller number. what are the numbers
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The number smaller are 3
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According to these three facts, which statements are true?
Yanka [14]
Q1) We have the following statements:

<span>1. Circle W has center (−3, 0) and radius 8.

We can write this statement as the following equation:

</span>(x-h)^2+(y-k)^2=r^2 \therefore (h,k)=(-3,0) \ and \ r=8 \\ \\ \therefore (x+3)^2+y^2=64
<span>
The graph of this equation is shown in Figure 1.

</span><span>2. Circle V is a translation of circle W, 2 units down.

To do this translation we add two units to the y-coordinate, so:

</span>(x+3)^2+(y+2)^2=64
<span>
The graph is shown in Figure 2.

</span><span>3. Circle V is a dilation of circle W with a scale factor of 2.

To do this dilatation we multiply both the center and the radius by the scale factor of 2, thus:

</span>(x+3)^2+y^2=64 \\ (h,k)=(-3,0) \\ (h_v,k_v)=2\times (-3,0)=(-6,0) \ and \ r_v=8\times2=16 \\ \\ (x+6)^2+y^2=256
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This circle is shown in Figure 3

So let's analyze each statement.

Q1.1) </span><span>The center of circle V is (−5, 0).

This is false. From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0).

Q1.2) 
</span><span>Circle V and circle W are similar.

Since all circles have the same shape even though they may be different sizes, then all circles are similar. Therefore, it is true that circle V and circle W are similar.

Q1.3) 
</span><span>The radius of circle V is 16.

From the statement 3 we can affirm that this is true. By applying the dilatation </span><span>with a scale factor of 2 we find out that the radius of the new circle is in fact equal to 16.

Q1.4) </span>Circle V and circle W have the same center. 

From the statement 2 we know that the new center is (-3, -2) and from 3 the new center is (-6, 0). On the other hand, the center of circle W is (-3, 0). From this, it follows that this statement is false.

Q2) Suppose x is any positive number.

We have two concentric circles as follows:

x\ \textgreater \ 0 \\ \\ Circle \ 1: Center \ (0,0) \ and \ radius \ 2x \\ \\ Circle \ 2: Center \ (0, 0) \ and \ radius \ 10x<span>

Q2.1) Why is circle 1 similar to circle 2?
</span><span>
If we perform a dilatation, that is, a </span>resizing of one circle, centered on the shared center, until both circles overlap, it will be true that the circles will always overlap no matter what size they are, thus, they are similar. In fact, as we said in above all circles are similar. 

Q2.2) 
<span>Circle 2 is a dilation of circle 1 with a scale factor of 0.2.

Suppose that:

</span>x=2
<span>
Then circle 1 is given by the following equation:

</span>x^2+y^2=4
<span>
If we dilate this circle </span><span>with a scale factor of 0.2 then:

</span>Circle \ 1: x^2+y^2=4 \\ Diameter \ 1=2r=2\times 2=4 \\ \\ (h,k)=(0,0) \\ (h_v,k_v)=0.2\times (0,0)=(0,0) \ and \ r_v=0.2\times 2=0.4 \\ \\ Circle \ 2:x^2+y^2=0.16 \\ Diameter \ 2=2\times 0.4=0.8 \\ \\ So: \\ \\ Diameter \ 1 \neq Diameter \2
<span>
So the statement b</span>oth circles have congruent diameters is false.

<span>Q2.3) Circle 2 is a dilation of circle 1 with a scale factor of 5.

We have the same equation for circle 1:

</span>x^2+y^2=4

Circle \ 1: x^2+y^2=4 \\ \\ Dilatation: \\ (h,k)=(0,0) \\ (h_v,k_v)=5\times (0,0)=(0,0) \ and \ r_v=5\times 2=10 \\ \\ Circle \ 2:x^2+y^2=100

Two circles have the same area if they have the same radius. Given that this is no applied to our circles, the statement circle 1 and circle 2 have equal areas is false.

8 0
3 years ago
The car travels with constant acceleration reaching a speed of v m/s after 6 seconds. The car then travels at a constant speed o
alisha [4.7K]

v=30m/s velocity is 30 ms-1

5 0
3 years ago
How do i get the second equation into standard form. A+B=C?​
timama [110]

\boxed{9x+2y=-16}

<h2>Explanation:</h2>

The standard form of the equation of a line is given by:

Ax+By=C \\ \\ A>0

To get the second equation into standard form let's follows these steps:

Step 1. Multiply both sides by 2:

y=\frac{-9x-16}{2} \\ \\ 2y=2\left(\frac{-9x-16}{2}\right) \\ \\ 2y=-9x-16

Step 2. Add 9x to both sides:

2y=-9x-16 \\ \\ 2y+9x=-9x-16 \\ \\ 9x+2y=-16

Finally, this equation in standard form is:

\boxed{9x+2y=-16}

<h2>Learn more:</h2>

System of equations: brainly.com/question/9214960

#LearnWithBrainly

7 0
3 years ago
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