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3 years ago

Solve using elimination -3-X=0 -3y=-3-2x

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

<h2>The solution is (x, y) = (-3, -1)</h2>

Solution:

Given, system of equations are:

-3 - x = 0 --------- eqn 1

-3y = -3 - 2x -------- eqn 2

From eqn 1,

- 3 - x = 0

Substitute x = -3 in eqn 2

-3y = - 3 - 2(-3)

-3y = -3 + 6

-3y = 3

Thus the solution is (x, y) = (-3, -1)

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3 years ago

State the converse, contrapositive, and inverse of each of these conditional statements a) If it snows tonight, then I will stay

marissa [1.9K]

Step-by-step explanation:

Consider the provided information.

For the condition statement $p \rightarrow q$ or equivalent "If p then q"

The rule for Converse is: Interchange the two statements.
The rule for Inverse is: Negative both statements.
The rule for Contrapositive is: Negative both statements and interchange them.

Part (A) If it snows tonight, then I will stay at home.

Here p is If it snows tonight, and q is I will stay at home.

Converse: If I will stay at home then it snows tonight.

$q \rightarrow p$

Inverse: If it doesn't snows tonight, then I will not stay at home.

$\sim p \rightarrow \sim q$

Contrapositive: If I will not stay at home then it doesn't snows tonight.

$\sim q \rightarrow \sim p$

Part (B) I go to the beach whenever it is a sunny summer day.

Here p is I go to the beach, and q is it is a sunny summer day.

Converse: It is a sunny summer day whenever I go to the beach.

$q \rightarrow p$

Inverse: I don't go to the beach whenever it is not a sunny summer day.

$\sim p \rightarrow \sim q$

Contrapositive: It is not a sunny summer day whenever I don't go to the beach.

$\sim q \rightarrow \sim p$

Part (C) When I stay up late, it is necessary that I sleep until noon.

P is I sleep until noon and q is I stay up late.

Converse: If I sleep until noon, then it is necessary that i stay up late.

$q \rightarrow p$

Inverse: When I don't stay up late, it is necessary that I don't sleep until noon.

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Contrapositive: If I don't sleep until noon, then it is not necessary that i stay up late.

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3 years ago

(15.2*0.25-48.51/14.7)/x=(13/44-2/11-5/66/2.50)1.2/(3.2+0.8(5.5-3.25)

goldfiish [28.3K]

Answer:

x = 41.67

Step-by-step explanation:

The above equation, would be simplified or divided into parts;

Therefore, the given equation becomes;

A/x = B/C

Where;

A = (15.2*0.25-48.51/14.7)

B = (13/44-2/11-5/66/2.50)1.2

C = 3.2+0.8(5.5-3.25)

x = unknown variable.

Part A

(15.2*0.25-48.51/14.7) = (15.2*0.25 - 3.3)

A = (3.8 - 3.3)

A = 0.5

Part B

(13/44-2/11-5/66/2.50)1.2 = (0.3 - 0.18 - 0.030) * 1.2

B = 0.09 * 1.2

B = 0.108

Part C

(3.2+0.8(5.5-3.25)

C = 4*(2.25)

C = 9

Substituting the values into the equation, we have;

0.5/x = 0.108/9

Cross-multiplying, we have;

9 * 0.5 = 0.108x

4.5 = 0.108x

x = 4.5/0.108

x = 41.67

6 0

3 years ago