Answer:
Down/down is the correct answer.
Explanation:
The down/down is the status of the interface when the speed of the ethernet mismatches that is configuration between the Cisco routers. Generally, it is the way of saying by the Cisco is "the connection" or the following ports are available for the connection but do not have one of them then, check their systems or the cables connection.
Answer:
is a generic description for how computers use multiple layers of protocol rules to communicate across a network.
Explanation:
OSI model stands for Open Systems Interconnection. The seven layers of OSI model architecture starts from the Hardware Layers (Layers in Hardware Systems) to Software Layers (Layers in Software Systems) and includes the following;
1. Physical Layer.
2. Data link Layer.
3. Network Layer.
4. Transport Layer.
5. Session Layer.
6. Presentation Layer.
7. Application Layer.
Hence, the Open Systems Interconnection (OSI) Reference Model is a generic description for how computers use multiple layers of protocol rules to communicate across a network.
Additionally, each layer has its unique functionality which is responsible for the proper functioning of the communication services.
Answer:
The answer is C. Rain Forests are important for many reasons
Explanation:
Answer:
Modern technology has developed
Explanation:
The development of technology may draw upon many fields of knowledge, including scientific, engineering, mathematical, linguistic, and historical knowledge, to achieve some practical result. ... For example, science might study the flow of electrons in electrical conductors by using already-existing tools and knowledge.
Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
