Answer:
<em>t = 1.51</em>
Step-by-step explanation:
<u>Exponential Model</u>
The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.
The model can be expressed as
![M=M_oe^{kt}](https://tex.z-dn.net/?f=M%3DM_oe%5E%7Bkt%7D)
In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.
The value of k is not precisely given in the question, we are assuming ![k=-0.2](https://tex.z-dn.net/?f=k%3D-0.2)
The model is now
![M=M_oe^{-0.2t}](https://tex.z-dn.net/?f=M%3DM_oe%5E%7B-0.2t%7D)
We are required to compute the time it takes the mass to reach one-half of its initial value:
![\displaystyle \frac{M_o}{2}=M_oe^{-0.2t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BM_o%7D%7B2%7D%3DM_oe%5E%7B-0.2t%7D)
Simplifying
![\displaystyle \frac{1}{2}=e^{-0.2t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B1%7D%7B2%7D%3De%5E%7B-0.2t%7D)
Taking logarithms
![\displaystyle ln\frac{1}{2}=ln(e^{-0.2t})=-0.2t](https://tex.z-dn.net/?f=%5Cdisplaystyle%20ln%5Cfrac%7B1%7D%7B2%7D%3Dln%28e%5E%7B-0.2t%7D%29%3D-0.2t)
Solving for t
![\displaystyle t=-\frac{ln\frac{1}{2}}{0.2}=1.51](https://tex.z-dn.net/?f=%5Cdisplaystyle%20t%3D-%5Cfrac%7Bln%5Cfrac%7B1%7D%7B2%7D%7D%7B0.2%7D%3D1.51)
It seems that the y-intercept is 1, so you will be adding 1 to the equation. When you make a chart, you find that each number grows by 1 as well.
From this information, you will find that the answer is
y = x + 1
Answer:
y = 2x + 3
Step-by-step explanation:
the slope is 2 so the line parallel will have a slope of 2
y-9 = 2(x-3)
y-9= 2x - 6
y = 2x +3
We need to find the other base also in order for us to find out what the area of this is.