What is 10^2 *10 plz help asap

A plane traveled 2565 miles with the wind in 4.5 hours and 2205 miles against the wind in the same amount of time. Find the spee

kherson [118]

Answer:

plane: 530 mi/h
wind: 40 mi/h

Step-by-step explanation:

Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...

speed = distance/time

p +w = (2565 mi)/(4.5 h) = 570 mi/h

p -w = (2205 mi)/(4.5 h) = 490 mi/h

Adding these speeds, we get ...

(p +w) +(p -w) = (570) +(490) mi/h

2p = 1060 mi/h

p = 530 mi/h

Then the speed of the wind is ...

w = 570 mi/h -p = (570 -530) mi/h = 40 mi/h

The plane's speed is 530 mi/h; the wind speed is 40 mi/h.

7 0

3 years ago

A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro

-Dominant- [34]

Answer:

$t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07$

The degrees of freedom are given by:

$df =n-1= 32-1=31$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{31}>3.07)=0.0044$

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example ( $\alpha=0.01,0.05, 0.1, 0.15$ ).

Step-by-step explanation:

Data given and notation

$\bar X=1.6$ represent the sample mean

$s=0.46$ represent the sample deviation

$n=32$ sample size

$\mu_o =1.35$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:

Null hypothesis: $\mu =1.35$

Alternative hypothesis: $\mu \neq 1.35$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07$

P-value

The degrees of freedom are given by:

$df =n-1= 32-1=31$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{31}>3.07)=0.0044$

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example ( $\alpha=0.01,0.05, 0.1, 0.15$ ).

5 0

3 years ago

PLSSSSSSS HELPPPPPPPP AS SOOON AS YOU CANNN

ludmilkaskok [199]

Answer:

238.64 cm

Step-by-step explanation:

4 0

3 years ago

A circle has a radius of 3. An arc in this circle has a central angle of 20°

Alla [95]

Answer:

The length of the arc is 1.0467

Step-by-step explanation:

First of all to solve this problem we need to use the circumferenc formula of a circle:

c = circumference

r = radius = 3

π = 3.14

c = 2π * r

we replace with the known values

c = 2 * 3.14 * 3

c = 18.84

The length of the circumference is 18.84

Now we have to divide the 20° by the 360° that a circle has, to know what part of the circle it represents

20° / 360° = 1/18

Now we multiply this fraction by the circumference and obtain the length of the arc

1/18 * 18.84 = 1.0467

The length of the arc is 1.0467

4 0

3 years ago

Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+

Hoochie [10]

The vertex form of the equation of a parabola is given by

$y-k=a(x-h)^2$

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

$y-(-2)=a(x-(-12))^2 \\ \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\ \\ y=ax^2+24ax+114a-2 \\ \\ y=x^2+24x+ \frac{114a-2}{a}$

For a = 1,

$y=x^2+24x+112$

<span>The parabola whose minimum is at (−12,−2) is given by the equation $y=x^2+ax+b$ , where a = 24 and b = 112.</span>

8 0

4 years ago