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vichka [17]
3 years ago
15

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 17 centimeters. An acute angle of the triangle is

labeled as x degrees. The side adjacent to the acute angle has length 15 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of cos x°?

Mathematics
2 answers:
mezya [45]3 years ago
8 0

Answer:

tan x degrees is opposite over adjacent, making it 8 over 6 and your answer 8 divided by 6

Vlad1618 [11]3 years ago
5 0

Answer:

\frac{15}{17}

Step-by-step explanation:

Refer the attached figure

Hypotenuse = AC = 17 cm

An acute angle of the triangle is labeled as x degrees.i.e.∠ACB = x

The side adjacent to the acute angle has length 15 centimeters i.e. BC = 15 cm

The side opposite to the acute angle has length 8 centimeters.i.e. AB = 8 cm

Now we will use trigonometric ratio

cos \theta  =\frac{Base}{Hypotenuse}

cos x  =\frac{BC}{AC}

So, cos x  =\frac{15}{17}

Hence the value of cos x° is \frac{15}{17}

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serious [3.7K]

Answer:

a) 0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

b) The expected number of at-bats until the next home run is 6.25.

Step-by-step explanation:

For each at bat, there are two possible outcomes. Either it is a home run, or it is not. The probability of an at bat resulting in a home run is independent of any other at-bat, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that Barry Bonds hits a home run on any given at-bat is 0.16

This means that p = 0.16

Part A: What is the probability that the next home run will be on his fifth at-bat?

0 on his next 4(P(X = 0) when n = 4)

Home run on his 5th at-bat, with 0.16 probability. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.16)^{0}.(0.84)^{4} = 0.49787136


0.49787136 *0.16 = 0.0797.

0.0797 = 7.97% probability that the next home run will be on his fifth at-bat.

Part B: What is the expected number of at-bats until the next home run?

The expected number of trials for n successes is given by:

E = \frac{n}{p}

In this question, n = 1, p = 0.16. So

E = \frac{1}{0.16} = 6.25

The expected number of at-bats until the next home run is 6.25.

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Answer:

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Step-by-step explanation:

Calculators help :)

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Hey!

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vekshin1

Answer:

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Step-by-step explanation:

Happy to help.

When we have numbers in parenthesis, we generally want to deal with those first. However, we can hit a rough patch when a variable is in there. Consider this:

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