Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
the dot plot, because box plot only shows the 5 number summary and histograms show ratios
In the binomial development, the main problem is calculation of binomial coefficients.
If we want to get term a∧8*b∧2 we see that this is the third member in binomial development (n 2) a∧n-2*b∧2
The given binomial is ((1/3)a∧2 - 3b)∧6, the first element is (1/3)a∧2, the second element is (-3b) and n=6 when we replace this in the formula we get
(6 2) * ((1/3)a∧2)∧(6-2) * (-3b)2 = (6*5)/2 * ((1/3)a∧2)∧4 *9b∧2= 15*(1/81)*9 *(a∧8b∧2) =
= 15*9* a∧8b∧2 = 135*a∧8b∧2
We finally get numerical coefficient 135
Good luck!!!
Answer:
Line TX or XT
Step-by-step explanation:
Planes always intersect in a line.
• Im sorry but we doesnt know the x number :( but dont worry to plot the diagram:
- substitute the number x (given) into the equation f(x)
- example: f(x) = x + 9 / x - 3
- then x given is 4
- therefore, f(x) = (4) + 9 / (4) - 3
- f(x) = 13 / 1 or 13
- then you plot at 13 on the graph :)
hope this helps ;/