I don't understand pls help

Mathematics

1 answer:

MrMuchimi3 years ago

3 0

Twilight was liked by half the class because if you add up the number of students you get 24 and half of 24 is 12
(Hope this helped)

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Frank starts off with $ 120 to spend on his shirts and shoes. Frank buys 3 shirts for $15.50 each. Shoes cost $32.50 each per pa

evablogger [386]

Shirts: 3 x 15.50 = 46.50

120 - 46.50 = 73.50 left to spend on shoes

73.50/32.50(cost per pair) = 2.26....so he was able to purchase 2 pairs of shoes.

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2 years ago

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

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3 years ago

Find the volume of the figure below. Round your answer to the nearest hundredth if necessary.

slamgirl [31]

Answer:

C. 225 km3

Step-by-step explanation:

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2 years ago

Which polynomial is equivalent to (2h − 3k)(h + 5k)?

shutvik [7]

2h^2 + 7hk -15k^2
you can use factoring

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3 years ago

Read 2 more answers

A typical acoustic guitar has a range of three octaves. When the guitar is tuned to "concert pitch," the range of frequencies fo

AfilCa [17]

Given a variable, x, the compound ineaquality representing the range from a to b inclusive of the variable is given by

$a\leqx\leqb$
where a is the least value and b is the greatest value.

Thus, given a variable f, representing the frequencies for the three octaves of a <span>typical acoustic guitar.
</span>
Where the range of the frequencies is between 82.4 Hertz and 659.2 Hertz inclusive.

The complex inequality, representing <span>the range of frequencies for a guitar tuned to "concert pitch"</span> is given by

$82.4\leq f\leq659.2$

6 0

3 years ago