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natima [27]
3 years ago
10

Solve this system of equations. y = 5x +20 and y = -2x -8

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

y = 0

x = -4

( x, y ) = ( -4 , 0 )

Step-by-step explanation:

y = 5x + 20

y = -2x - 8

Substitute

5x + 20 = -2x - 8

Add 8 on both sides

5x + 20 + 8 = -2x - 8 + 8

5x + 28 = -2x

Subtract 5x on both sides

5x - 5x + 28 = -2x - 5x

28 = -7x

Divide by -7 on both sides

28/-7 = -7x/-7

-4 = x

Now that you have x, you can substitute it in one of the equations that was given to find the value of y.

y = 5x + 20

y = 5(-4) + 20

y = -20 + 20

y = 0

Or....

y = -2x - 8

y = -2(-4) - 8

y = 8 - 8

y = 0

They will both be 0 no matter what

Point form = ( -4, 0 )

Hope this helped

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What is the circumference of a circle with a diameter of 5.8 inches? Use 3.14 for π and round the answer to the nearest tenth. A
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Answer: B) 18.2 inches

Step-by-step explanation:

We know that the circumference of a circle is given by :-

\text{Circumference}=\pi d

Given : Diameter of a circle = 5.8 inches

Then, the circumference of the circle will be :-

\text{Circumference}=(3.14)\times5.8=18.212\approx18.2\text{inches}

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The population of New York City is about 8.18 × 10^6. The population of Las Vegas is about 5.84 × 10^5. About how many times lar
ioda

Answer:

D. 14 times

Step-by-step explanation:

The population of New York City is about 8.18 × 10^6. This is an estimation. The population of Las Vegas is about 5.84 × 10^5. This is also an estimation. We want to determine the number of times that population of new York is more than that of las Vegas. It's like saying how many las Vegas are the in New york.

This is done by dividing the population of new York by the population of las Vegas. It becomes

8.18 × 10^6 / 5.84 × 10^5

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3 years ago
Find the length of a rectangle lot with a perimeter of 66 feet if the length is 3 times more than 4 times the width.
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Answer:

27 feet

Step-by-step explanation:

We are told in the question that a lot is rectangular in shape

The perimeter of a rectangle

= 2(L + W)

= 2L + 2W

Where

L = Length of the rectangle

W = Width of the rectangle

From the question,

P = 66 feet

The length is 3 times more than 4 times the width

L = 3 + (4 × W)

= 3+ (4W) = 3 + 4W

Hence,

P = 2L + 2W

66 = 2(3 + 4W) + 2W

66 = 6 + 8W + 2W

Collect like terms

66 - 6 = 8W + 2W

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W = 60/10

W = 6

The Width of the rectangular lot = 6 feet

To find the length

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L = Perimeter - 2W/2

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L = 66 - 12/2

L = 54/2

L = 27

Therefore the Length of the rectangular lot = 27 feet

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3 years ago
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