The answer is B. Unsaturated hydrocarbons will be hydrocarbons that have twofold or triple covalent securities between neighboring carbon particles. Those with no less than one carbon-to-carbon twofold bond are called alkenes and those with no less than one carbon-to-carbon triple bond are called alkynes.
Answer:
Degree of ionization = 0.0377
pH of the solution = 1.769
Explanation:
Initial concentration of HF = 0.45 M
Initial 0.45 0 0
At equi 0.45 - x x x
Equilibrium constant = ![\frac{[H^+][F^-]}{HF}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B%5D%5BF%5E-%5D%7D%7BHF%7D)
![6.8 \times 10^{-4}= \frac{[x][x]}{0.45 - x}](https://tex.z-dn.net/?f=6.8%20%5Ctimes%2010%5E%7B-4%7D%3D%20%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B0.45%20-%20x%7D)
x = 0.017 M
x = Cα
α = Degree of ionization
C = Concentration
Degree of ionization = 
![pH = -log[H^+]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5BH%5E%2B%5D)
[H^+]=0.017 M
![pH = -log[0.017]](https://tex.z-dn.net/?f=pH%20%3D%20-log%5B0.017%5D)
= 1.769
The total pressure is 6.7 atm. The mole fractions of O₂ and Ar are 0.42 and 0.037.
<em>p</em>(Tot) = <em>p</em>(N₂) + <em>p</em>(O₂) + <em>p</em>(Ar) + <em>p</em>(He) = 3.5 atm + 2.8 atm + 0.25 atm + 0.15 atm = 6.7 atm
χ(O₂) = p(O₂)/p(Tot) = 2.8 atm/6.7 atm = 0.42
χ(Ar) = p(Ar)/p(Tot) = 0.25 atm/6.7 atm = 0.037
Answer:
Sorry mate! I can't understand this language...
