Answer:
a) 0.2118 mol of I₂ is produced.
b) 49.93 g of I₂ is produced.
Explanation:
a) The balanced equation shows that to produce 1 mol of I₂ we need 2 mol of CuCl₂ . Therefore, the amount of I₂ produced will always be half the amount of CuCl₂ given.
b) In order to calculate the mass of I₂ produced we need to know its molar mass:
Each mole of I₂ weighs 253.8 g, therefore MM = 253.8 g/mol.
Base on the problem given, it shows that the rate law for this reaction is directly proportional. The relationship between the reactants Z and Y that is proportional to the cube of [Z], it shows the concentrations of reactants is expressed by the rate law.
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Answer:
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Mole fraction is the ratio of the constituent moles to the total constituents. The mole fraction of sodium chloride is 0.0443.
<h3>What is a mole fraction?</h3>
A mole fraction is the proportion of the moles of the component in a total component present.
In 100 gm of solution 13.0 5 means, there is 13.0 gm of sodium chloride present. The mass of water is calculated as,
100 - 13.0 = 87.0 gm
Moles of sodium chloride is calculated as:
Moles of water are calculated as:
Now, moles fraction is calculated by dividing moles of sodium chloride by total moles as,
Therefore, the mole fraction of sodium chloride is 0.0443.
Learn more about mole fraction here:
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