The number of bonds for a neutral atom is equal to the number of electrons in the full valence shell (2 or 8 electrons) minus the number of valence electrons. This method works because each covalent bond that an atom forms adds another electron to an atoms valence shell without changing its charge.
The molarity of the acid given the data from the question is 0.30 M
<h3>Balanced equation </h3>
2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O
From the balanced equation above,
- The mole ratio of the acid, HNO₃ (nA) = 2
- The mole ratio of the base, Ba(NO₃)₂ (nB) = 1
<h3>How to determine the molarity of the acid</h3>
From the question given above, the following data were obtained:
- Volume of acid, HNO₃ (Va) = 39.7 mL
- Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
- Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
- Molarity of acid, HNO₃ (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 39.7) / (0.25 × 24) = 2
(Ma × 39.7) / 6 = 2
Cross multiply
Ma × 39.7 = 6 × 2
Ma × 39.7 = 12
Divide both side by 39.7
Ma = 12 / 39.7
Ma = 0.30 M
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Na2S2O3(aq) + 4Cl2( g) + 5H2O = 2NaHSO4(aq) + 8HCl(aq)
1)How many moles of HCl can form from 0.21 mol of Cl2?
0.21 mol Cl2 ( 8 mol HCl / 4 mol Cl2 ) = 0.42 mol HCl
2)How many moles of H2O are required for the reaction of 0.18 mol of Cl2?
0.18 mol Cl2 ( 5 mol H2O / 4 mol Cl2 ) = 0.225 mol H2O
3)How many moles of H2O react if 0.50 mol HCl is formed?
0.50 mol HCl ( 5 mol H2O / 8 mol HCl ) = 0.3125 mol H2O
Options if it’s true or false true
Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

That means:

From that equation we can calculate Volume of gas at a certain pressure:
P₁=Initial pressure
V₁=Initial volume
P₂=Final pressure
V₂= Final volume
Here P₁, initial pressure is given as 85.0 kPa
V₁, initial volume is given as 525 mL
P₂, final pressure is 65.0 kPa

so,
V_{2}=85\times 525\div 65
=686 mL
Volume of gas will be 686 mL.