8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.
YZ is the diameter, so arc YZ = 360°/2 = 180°
arc XZ = 360° - arc YZ - arc YWX = 360° - 180° - 100° = 80°
∠XYZ is an inscribed angle <span>so it is equal to half the arc XZ
</span>∠XYZ = 80°/2 = 40°
Answer:
The water is 208.22ft from the tug boat
Step-by-step explanation:
The governing equation is 
y is the height above the ocean
x is the distance from the tugboat
if y= 6ft, the equation will now become

we can arrange this properly to form a quadratic equation by grouping like terms.

solving quadratically we have two values of x as 208.22ft and 0.873 ft.
We can take a more realistic value as a solution to our problems:
208.22ft
6.70820393249936 i hope this helps