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SSSSS [86.1K]
2 years ago
5

The rent for an apartment is $800 per month. The landlord charges one month's rent as a deposit plus a nonrefundable damage cost

of $250.
The expression 800(n + 1) + 250 represents the cost of the renting the apartment for n months. Write the expression in simplified form.
please help me i have a test tmr
Mathematics
1 answer:
Step2247 [10]2 years ago
3 0

Answer:

800n+1050

Step-by-step explanation:

800(n+1)+250 = 800n+800+250 = 800n+1050.

Hope this helps!

Good luck with your test + I hope you do well on it.

Please mark me as brainliest!

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Its D if you want to give it a shoot but im 75% sure is D hope you got it right. :)
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3 years ago
Write 0.65% as a decimal
MAXImum [283]
The answer would be: 0.0065
4 0
3 years ago
Read 2 more answers
An A-frame house is 45 feet high and 32 feet wide. Find the measure of the angle that the roof makes with the floor. Round to th
Flura [38]

Answer:

Angle, \theta=70.4^{\circ}

Step-by-step explanation:

We have, an A-frame house is 45 feet high and 32 feet wide. It is required to find the measure of the angle that the roof makes with the floor.

The attached figure shows the A frame. Let \theta is the angle that the roof makes with the floor. So,

\tan\theta=\dfrac{45}{16}\\\\\tan\theta=2.81\\\\\theta=\tan^{-1}(2.81)\\\\\theta=70.4^{\circ}

So, the angle of 70.4 degrees is the angle that the roof makes with the floor.

4 0
3 years ago
​together, steve and tom sold 7777 raffle tickets for their school. steve sold 1414 more than twicetwice as many raffle tickets
storchak [24]
Steve = S , Tom = T
1) S+T = 7777
2) S= 1414 + 2T

put 2) in 1)

1414+2T + T = 7777
1414 +3T = 7777
3T = 6363
so T = 2121
then Steve sold 1414+2(2121) = 1414+4242=5656 tickets
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5 0
4 years ago
Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of
sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error M is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

52% of Independents in the sample opposed the public option.

This means that p = 0.52

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}

0.01\sqrt{n} = 0.8218

\sqrt{n} = \frac{0.8218}{0.01}

\sqrt{n} = 82.18

\sqrt{n}^{2} = (82.18)^{2}

n = 6754.2

A sample size of 6755 or higher would be appropriate.

3 0
3 years ago
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