To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer: 13km
Step-by-step explanation:
Answer:
5) Part A: The rate of change, also known as the slope, is the "0.6x" part of the equation. It means that for every week the puppy is alive, x, that number is multiplied by 0.6 pounds.
Part B: The y-intercept is 4 pounds, which represents a puppy being 4 pounds at birth.
Part C: y = 0.6x + 4
y = 0.6(8)+4
y = 8.8
At 8 weeks, a puppy is estimated to be 8.8 pounds.
Part D: y = 0.6x + 4
22 = 0.6 + 4
-4 -4
18 = 0.6x
18/0.6 = 0.6x/0.6
30 = x
It would take a puppy 30 weeks to reach 22 pounds.
Answer:
<em>(d).</em>
Step-by-step explanation:
The y-intercept (0, 3) is initial value of graph ⇒ (d). <em>3 miles; it represents the original distance of the bird from its nest</em>
Answer:
324
Step-by-step explanation:
