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Sonbull [250]
3 years ago
7

adult tickets cost $10 and children's tickets to a show cost $5. if the number of children's tickets was twice the number of adu

lt tickets, how many of each type of tickets was sold if $800 was collcted in tickets sales? ( make sure you write a legend stating what your variable represents)
Mathematics
1 answer:
Brrunno [24]3 years ago
7 0
X=amount of children tickes sold
y=amount of adult tickets sold

2 times of children as adult
x=2y

total cost is 800
5x+10y=800
divide both sides by 5
x+2y=160
x=2y
2y+2y=160
4y=160
divie by 4
y=40

x=2y
x=2(40)
x=80


80 children tickets
40 adult tickets
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Step-by-step explanation:

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Karen had 7 items in her shopping cart with different prices. Her mean cost of these items was $4.02. At the register, she added
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x≠-1,1

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5 0
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Read 2 more answers
A manufacturer produces a commodity where the length of the commodity has approximately normal distribution with a mean of 6.5 i
zavuch27 [327]

The probablity that the sample's mean length is greate than 6.3 inches is0.8446.

Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.

We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.

Probability is the likeliness of happening an event. It lies between 0 and 1.

Probability is the number of items divided by the total number of items.

We have to use z statistic in this question because the sample size is greater than 30.

μ=6.5

σ=0.5

n=46

z=X-μ/σ

where μ is mean and

σ is standard deviation.

First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.

z=6.3-6.5/0.5

=-0.2/0.5

=-0.4

p value from z table is 0.3446

Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.

Hence the probability that the mean length is greater than 6.3 inches is 0.8446.

Learn more about probability at brainly.com/question/24756209

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