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adell [148]
3 years ago
10

A flat-screen television was marked down by 35 percent, which reduced its price by $115.65. What was the original cost of the te

levision before it was marked down?
Mathematics
2 answers:
aniked [119]3 years ago
5 0

Answer: 330.43

Step-by-step explanation:

He´s right

Vera_Pavlovna [14]3 years ago
3 0
Marked down by 35% this decreased it by 115.65 thhat means that 115.65 is 35% of original find original 35%=35/100=7/20 'of' means multiply 115.65=7/20 times original multiply both sides by 20/7 to clear fraction (20/7 times 7/20=140/140=1) 2313/7=original 330.428=original round 330.43 original price=$330.43
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Do positive or negative messages have a greater effect on behavior? Forty-two subjects were randomly assigned to one of two trea
Alex_Xolod [135]

Answer:

We conclude that a negative message results in a lower mean score than positive message.

Step-by-step explanation:

We are given that Forty-two subjects were randomly assigned to one of two treatment groups, 21 per group.

The 21 subjects receiving the negative message had a mean score of 9.64 with standard deviation 3.43; the 21 subjects receiving the positive message had a mean score of 15.84 with standard deviation 8.65.

<em>Let </em>\mu_1<em> = population mean score for negative message</em>

<em />\mu_2<em> = population mean score for positive message</em>

SO, Null Hypothesis, H_0 : \mu_1-\mu_2\geq0  or  \mu_1\geq \mu_2    {means that a negative message results in a higher or equal mean score than positive message}

Alternate Hypothesis, H_A : \mu_1-\mu_2  or  \mu_1   {means that a negative message results in a lower mean score than positive message}

The test statistics that will be used here is <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;

                     T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1+_n__2-2

where, \bar X_1 = sample mean score for negative message = 9.64

\bar X_2 = sample mean score for positive message = 15.84

s_1 = sample standard deviation for negative message = 3.43

s_2 = sample standard deviation for positive message = 8.65

n_1 = sample of subjects receiving the negative message = 21

n_2 = sample of subjects receiving the positive message = 21

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} }  =  \sqrt{\frac{(21-1)\times 3.43^{2}+(21-1)\times 8.65^{2}  }{21+21-2} }  = 6.58

So, <u><em>the test statistics</em></u>  =  \frac{(9.64-15.84)-(0)}{6.58 \times \sqrt{\frac{1}{21}+\frac{1}{21}  } }  ~  t_4_0

                                     =  -3.053

<em>Now at 0.05 significance level, the t table gives critical value of -1.684 at 40 degree of freedom for left-tailed test. Since our test statistics is less than the critical value of t as -3.053 < -1.684, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.</em>

Therefore, we conclude that a negative message results in a lower mean score than positive message.

7 0
3 years ago
A number decreased by fifteen is less than two
Afina-wow [57]

Answer: x - 15 < 2

Step-by-step explanation: x is a variable indicating a number, and since it said decreased by meaning you subtract an then by 15 and less than two

5 0
3 years ago
Please help me out!!!!!!!!!!
SOVA2 [1]
4(3)^2-3(3)+7
36-9+7
34
g(3)=34
8 0
3 years ago
Somebody help thanks
slamgirl [31]
Really simple, All you have to do is find out how many meters are in a kilometer, which is 1000 meters, and then you have to multiply 1000 with 190 which is 190000. Hope i helped!
6 0
3 years ago
A study of teenage drivers found that 63% text while driving and 30% have a car accident in their first year of driving. 21% of
Kipish [7]

Answer:

33.33%

Step-by-step explanation:

63% of teenage drivers text while driving

21% of teenage drivers text while driving and have car accident in their first year

This means that a third of teenage drivers that text while driving get involved in a car accident during their first year, 33.33% is the probability then

6 0
3 years ago
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