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Leya [2.2K]
3 years ago
10

"a number increased by thirty-five"

Mathematics
1 answer:
Nata [24]3 years ago
3 0

Answer:

x + 35

Step-by-step explanation:

Let x represent a number

Increased means to add

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Which algebraic expressions are polynomials
ivolga24 [154]

Answer:

2,3,5,6

Step-by-step explanation:

4 0
3 years ago
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HELP. It’s LOG form. Since were out of school I forgot how I did this and it’s due so it would be a life saver.
____ [38]

Answer:

see below

Step-by-step explanation:

exponent to log: a^b = c ---> logₐc = b

ie. question 6

log ₁₀(3x+1) = 2 -----> 10^{2} = 3x+1

that will get you through questions 1 to 3, 5 to 6, and 8

in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3

for questions 7 and 9,

remember that:

logₐc + logₐd = logₐ(cd)

logₐc - logₐd = logₐ(\frac{c}{d})

remember change of base is log_{a} b = \frac{log_xb}{log_xa}, this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e

4 0
4 years ago
Are angles 1 and 2 a linear pair? Yes or no.
Svetllana [295]
Yes because they are equal values
3 0
3 years ago
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How much liquid will fit in the glass shown? Round your answer to the nearest hundredth.
nikitadnepr [17]

Answer:

The cup can hold 497.17 in³ of liquid.

Step-by-step explanation:

The shape of the glass can be divided in two figures, the first one is a cilinder with radius 5 in and height 3 in, while the second is a half sphere with radius 5 in. Therefore in order to calculate the volume of liquid the glass can hold we need to calculate the volume of each of these and sum them.

Vcilinder = pi*r²*h = 3.14*5²*3 = 235.5 in³

Vhalfsphere = (2*pi*r³)/3 = (2*3.14*5³)/3 = 261.67 in³

Vcup = Vcilinder + Vhalfsphere = 235.5 + 261.67 = 497.17 in³

The cup can hold 497.17 in³ of liquid.

5 0
3 years ago
Find the value of x. pls hurry big reward.
dybincka [34]
X = 8
18+90 = 108
180-108=72
72/9=8
4 0
4 years ago
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