Find f'(x) f(x)=(1-2x^2)^3
1 answer:
Answer: f'(x) = 12x + 48x³ - 48x⁵
<u>Step-by-step explanation:</u>
f(x) = (1 - 2x²)³
= (1 - 2x²)(1 - 4x² + 4x⁴)
1 - 4x² + 4x⁴
<u> -2x² + 8x⁴ - 8x⁶</u>
= 1 - 6x² + 12x⁴ - 8x⁶
f'(x) = 0 -2(6)x²⁻¹ + 4(12)x⁴⁻¹ - 6(8)x⁶⁻¹
= 12x + 48x³ - 48x⁵
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