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Mariana [72]
3 years ago
9

Find f'(x) f(x)=(1-2x^2)^3

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:  f'(x) = 12x  + 48x³ - 48x⁵

<u>Step-by-step explanation:</u>

f(x) = (1 - 2x²)³

     = (1 - 2x²)(1 - 4x² + 4x⁴)

         1 - 4x² + 4x⁴

        <u>    -2x² + 8x⁴ - 8x⁶</u>

     =  1 - 6x² + 12x⁴ - 8x⁶

f'(x) = 0 -2(6)x²⁻¹ + 4(12)x⁴⁻¹ - 6(8)x⁶⁻¹

      =     12x  + 48x³ - 48x⁵

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