Three hundred ninety six divided by twenty four = 16.5
Answer:
the answer is d
Step-by-step explanation:
Answer:
1296√3 cubic units
Step-by-step explanation:
The volume of the prism will be the product of its base area and its height. Since it circumscribes a sphere with diameter 12, that is the height of the prism.
The central cross section of the sphere is a circle of radius 6, and that will be the size of the incircle of the base. That is, the base will have an altitude of 3 times that incircle radius, and an edge length of 2√3 times that incircle radius. Hence the area of the triangular base is ...
B = (1/2)(6×2√3)(6×3) = 108√3 . . . . . square units
The volume of the prism is then ...
V = Bh = (108√3)(12) = 1296√3 . . . cubic units
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<em>Comment on the geometry</em>
The centroid of an equilateral triangle is also the incenter and the circumcenter. The distance of that center from any edge of the triangle is 1/3 the height of the triangle. So, for an inradius of 6, the triangle height is 3×6 = 18. The side length of an equilateral triangle is 2/√3 times the altitude, so is 12√3 units for this triangle.
About three years. Hope it helps!
Check the picture below.
so the <u>triangular prism</u> is really 3 rectangles and two triangles stacked up to each other at the edges, so if we simply get the area of each figure individually and sum them up, that's the area of the prism.
let's notice, the triangles have a base of 2.4 and a height/altitude of 1.
![\bf \stackrel{\textit{2 triangles's area}}{2\left[ \cfrac{1}{2}(2.4)(1) \right]}~~+~~\stackrel{\textit{right rectangle}}{(2\cdot 1.5)}~~+~~\stackrel{\textit{left rectangle}}{(2\cdot 1.7)}~~+~~\stackrel{\textit{bottom rectangle}}{(2\cdot 2.4)} \\\\\\ 2.4+3+3.4+4.8\implies 5.4+8.2\implies 13.6](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B2%20triangles%27s%20area%7D%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%282.4%29%281%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bright%20rectangle%7D%7D%7B%282%5Ccdot%201.5%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bleft%20rectangle%7D%7D%7B%282%5Ccdot%201.7%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Bbottom%20rectangle%7D%7D%7B%282%5Ccdot%202.4%29%7D%20%5C%5C%5C%5C%5C%5C%202.4%2B3%2B3.4%2B4.8%5Cimplies%205.4%2B8.2%5Cimplies%2013.6)