Find f'(x) f(x)=(1-2x^2)^3

Mathematics

1 answer:

Hunter-Best [27]3 years ago

3 0

Answer: f'(x) = 12x + 48x³ - 48x⁵

<u>Step-by-step explanation:</u>

f(x) = (1 - 2x²)³

= (1 - 2x²)(1 - 4x² + 4x⁴)

1 - 4x² + 4x⁴

= 1 - 6x² + 12x⁴ - 8x⁶

f'(x) = 0 -2(6)x²⁻¹ + 4(12)x⁴⁻¹ - 6(8)x⁶⁻¹

= 12x + 48x³ - 48x⁵

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