Answer:
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy
Step-by-step explanation:
(9xy^2 + 12x^3y^4 − 6x) ÷ 3x = 4x^2y^4 + 3y^2 − 2 (False: 9xy^2:3x=3y^2)
25x^4y^2 + 10x^2y^4 − 15y) ÷ 5y = 5x^4y + 2x^3y^2 − 3 (False: 10x^2y^4:5y=2x^2y^3)
(16x^4y^2 + 24x^2y^2 − 8xy^2) ÷ 4xy = 4x^4y + 6xy− 2y(False: 16x^4y^2:4xy=4x^3y)
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy (True)
The answer is A because the “hops” are jumping over two spaces which equals 2/10 simplified to 1/5. and since the number line stops at 2 it’d be 2 and not 1. If you do the keep change flip method for answer option one you get 10.
Answer: $9
Step-by-step explanation:
Let the cost for adults be a
Let the cost for students be b.
The first van transported 2 adults and 5 students and cost $77. This will be:
2a + 5b = $77
The second van transported 2 adults and 7 students and cost $95. This will be:
2a + 7b = $95
2a + 5b = 77 ...... equation i
2a + 7b = 95 ........ equation ii
Subtract equation ii from I
-2b = -18
b = 18/2
b = $9
An student cost $9
Put the value of b into equation i
2a + 5b = 77
2a + 5(9) = 77
2a + 45 = 77
2a = 77 - 45
2a = 32
a = 32/2
a = 16
An adult costs $16
Answer:
Step-by-step explanation:
6
Answer:
-16x + 14 4/5
Step-by-step explanation:
Perform the indicated multiplication. We get:
2x + 14 - 18x + 4/5
Next, combine like terms: We get:
-16x + 14 4/5
