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Natasha_Volkova [10]
3 years ago
13

Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass o

f the empty crucible (tare weight) was 17.410 g. calculate the concentration of the ba(oh)2 solution from these data.
Chemistry
1 answer:
marusya05 [52]3 years ago
6 0
<span>The weight of the precipitate was 17.550g - 17.410g = 0.140g. From a 10ml sample, this means the concentration was 0.140g / 10ml, which is equal to 0.014g/ml.</span>
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