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Natasha_Volkova [10]
3 years ago
13

Suppose that for the same 10.0 ml sample described in q3, the mass of the crucible with precipitate was 17.550 g, and the mass o

f the empty crucible (tare weight) was 17.410 g. calculate the concentration of the ba(oh)2 solution from these data.
Chemistry
1 answer:
marusya05 [52]3 years ago
6 0
<span>The weight of the precipitate was 17.550g - 17.410g = 0.140g. From a 10ml sample, this means the concentration was 0.140g / 10ml, which is equal to 0.014g/ml.</span>
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2 years ago
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Consider the balanced chemical reaction below. When the reaction was carried out, the calculated theoretical yield for carbon di
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Answer:

Percent Yield = 94.237%

Explanation:

CO = Carbon Dioxide = Molar Mass 28g/mol

C = Carbon = 12g/mol

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Suppose 550.mmol of electrons must be transported from one side of an electrochemical cell to another in 49.0 minutes. Calculate
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Explanation:

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1 mmol = 0.001 mol

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Charge on N electrons : Q

Q = N\times 1.602\times 10^{-19} C

Duration of time charge allowed to pass = T = 49.0 min = 49.0 × 60 seconds

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Size of current : I

I=\frac{Q}{T}=\frac{N\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}

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I=\frac{0.550 mol\times 6.022\times 10^{23} mol^{-1}\times 1.602\times 10^{-19} C}{49.0\times 60 seconds}=18.047 A\approx 18.0 A

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3 years ago
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Answer:

Option C. 13.5 atm

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From the question given above, the following data were obtained:

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The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:

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Therefore, the total pressure in the container is 13.5 atm

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