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Gelneren [198K]
3 years ago
9

A gas sample is held at constant temperature. What happens to the pressure of the sample if the volume is doubled and the number

of molecules is doubled?\
Chemistry
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

Explanation:

Step 1: Data given

Temperature = constant

Volume will be doubled

Number of molecules will be doubles

Step 2:

p*V = n*R*T

⇒ gas constant and temperature are constant

Initial pressure = n*R*T / V

Initial pressure = 2*R*T/2

Initial pressure =  RT

Final pressure = 4*RT / 4

Final pressure = R*T

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

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Molecules have ionization energies, just like atoms do. The ionization energy for molecular oxygen, for example, is 1314 kJ/mol.
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Answer:

91.1835 nm

Explanation:

Given that the ionization energy of the oxygen molecule = 1314 kJ/mol

It means that

1 mole of oxygen molecules can be ionized by the energy = 1314 kJ = 1314000 J

1 mole of molecules contains 6.022 × 10²³ atoms

So,

6.022 × 10²³ atoms of oxygen molecules can be ionized by the energy = 1314000 J

1 atom require \frac{1314000}{6.022\times 10^{23}}\ J of energy

Energy = 2.18\times 10^{-18}\ J

Also

E=\frac {h\times c}{\lambda}

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h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

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So,

\lambda=\frac {h\times c}{E}

\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{2.18\times 10^{-18}}\ m

\lambda=91.1835\times 10^{-9}}\ m

Also,

1\ nm=10^{-9}}\ m

So, wavelength = 91.1835 nm

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