Question

What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m

Answer 1

Answer:

60.6528 kg

Step-by-step explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

$V=\frac{4}{3}\pi r^3\\\\V=\frac{4}{3}\pi (\frac{18}{100})^3\\\\V=\frac{4}{3}\pi (0.005832)\\\\V=0.007776$

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

$\rho=\frac{mass}{volume}\\ \\7800\: kg/m^3=\frac{mass}{0.007776\: m^3}\\\\mass=60.6528\:kg$

Thus, the mass of the solid ball of iron is 60.6528 kg