Add -7 to both sides so that the equation becomes -3x^2 + 6x + 2 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -6 ± √((6)^2 - 4(-3)(2)) ] / ( 2(-3) )
x = [-6 ± √(36 - (-24) ) ] / ( -6 )
x = [-6 ± √(60) ] / ( -6)
x = [-6 ± 2*sqrt(15) ] / ( -6 )
x = 1 ± -sqrt(15)/3
The answers are 1 + sqrt(15)/3 and 1 - sqrt(15)/3.
Step-by-step explanation:
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Answer: p^2 + q^2 = r^2
Step-by-step explanation:
Pythagorean Theorem = a^2 + b^2 = c^2
P = a (leg)
q = b (leg)
r = c (Hypotenuse)
I would say true because the empty places do not have a value.
