Answer:
<em>Explanation below</em>
Step-by-step explanation:
<u>Vertical Shift of Functions</u>
Given a linear function
y = mx + b
The value of b is called the y-intercept or the y-coordinate where the line crosses the y-axis. If the function is shifted up by a value of k, then the new function is:
y' = mx + b + k
Similarily to shift the function down, the value of k is subtracted:
y''= mx + b - k
We are given the function:
1) To shift up the line, we select a value of k=10. The new shifted-up function is:
2) To shift down the line, we select a value of k=5. The new shifted-down function is:
3) To shift to the origin, we must select a specific value of k that cancels the y-intercept. We must shift down by k=2:
This new function has the y-intercept equal to 0
The radiusof <span> (x^2−6x)+(y^2−10y)=−18 </span>is 4
The line from Bob to the Peak of the mountain is the hypotenuse, and Bob's distance from the center base of the mountain is one leg, and the height of the mountain is the other leg. The 23o29' angle is between the hypotenuse and the leg from Bob to the Base (16194.6 ft). The side opposite to the angle is the height of the mountain.
The relevant trig function, then, is the tangent:
Tangent x = opposite side/adjacent side
Here the adjacent side is 16,194.6 feet and the opposite side is the height of the mountain. So
Tan(23.483o) = height/(16,194.6)
Solve for the height.
Step 2 i believe im not sure tho.