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myrzilka [38]
3 years ago
13

A manufacturer determines that the cost of making a computer component is $2.161616. Write the cost as a fraction and as a mixed

number. PLEASEEEE HELP ME IM SO CONFUSED ASAP!!!!
Mathematics
2 answers:
Vaselesa [24]3 years ago
8 0

Answer:

The cost in a fraction is \$\frac{135,101}{62,500}.

The cost in a mixed number is 2\frac{10101}{62500}.

Step-by-step explanation:

Cost of making a computer component  = $2.161616

2.161616=\frac{2161616}{1,000,000}

Divide the whole equation from 4 until or unless you get number indivisible by 4 in numerator or in denominator

=\frac{135,101}{62,500}

Divide the numerator by denominator:

Quotient\frac{Remainder}{Divisor}

2\frac{10101}{62500}

Cost of making a computer component in fraction :

= \$ \frac{135,101}{62,500}

Cost of making a computer component in mixed number:

= \$2\frac{10101}{62500}

weqwewe [10]3 years ago
7 0
\bf 2.16161616\overline{16}\\\\
-------------------------------\\\\

\bf \textit{let's say }x=2.16161616\overline{16}\impliedby 
\begin{array}{llll}
\textit{now, let's multiply it by a power}\\
\textit{of 10, so the repetitive part is at}\\
\textit{the left-side, thus 100}
\end{array}
\\\\\\
\begin{array}{llll}
100\cdot 2.16161616\overline{16}\implies 216.161616\overline{16}&\implies 214+2.161616\overline{16}\\
\qquad \qquad \uparrow &\qquad \qquad \uparrow \\
\qquad 100\cdot x&\qquad \quad 214+x
\end{array}

\bf 100x=214+x\implies 100x-x=214\implies 99x=214
\\\\\\
x=\cfrac{214}{99}\implies x=2\frac{16}{99}
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3 years ago
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Researchers fed mice a specific amount of Toxaphene, a poisonous pesticide, and studied their nervous systems to find out why To
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Answer:

a. The mean refractory period= 1.85 and the standard error = 0.06455

b.  90% confidence interval for the mean absolute refractory period for all mice when subjected to the same treatment = 1.6981, 2.0019

c. Yes, the data give good evidence to support this theory

Step-by-step explanation:

a.  The table below shows the calculations:

                 X                (X-mean)^2

                1.7             0.0225

                1.8                 0.0025

                1.9                 0.0025

                2.0                 0.0225

Total        7.4                  0.05

Sample size: n=4

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The sample standard deviation, s = \sqrt{\frac{\sum \left ( x-\bar{x} \right )^{2}}{n-1}}=0.1291

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b. Degree of freedom: df = n-1 = 3

Critical value of t for 90% confidence interval is: 2.3534

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The p-value is: 0.0017

We reject the null hypothesis because p-value is less than 0.05 . This indicates that the data gave good evidence to support this theory.

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