Answer:
The histogram of the sample incomes will follow the normal curve.
Step-by-step explanation:
According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.
In this case the researches wants to determine the monthly gross incomes of drivers for a ride sharing company.
He selects a sample of <em>n</em> = 200 drivers and ask them their monthly salary.
As the sample selected is quite large, i.e. <em>n</em> = 200 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.
Thus, the histogram of the sample incomes will follow the normal curve.
Answer:
<u>Part A:</u><u> x = -24</u>
<u>Part B: </u><u>n = 2</u>
Step-by-step explanation:
<u>Part A:</u>
The algebraic expression for: "StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3" will be ⇒ 
Multiply both sides by 6
∴ 
∴
∴ 2x + 4*12 = x + 3 *14 - 18
∴ 2x - x = 3 * 14 - 18 - 4 * 12 = -24
<u>∴ x = -24</u>
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<u>Part B:</u>
The algebric expression for: "StartFraction one-half EndFraction left-parenthesis n minus 4 right-parenthesis minus 3 equals 3 minus left-parenthesis 2 n plus 3 right-parenthesis" will be ⇒ 
Multiply both sides by 2
(n-4) - 6 = 6 - 2(2n+3)
n - 4 - 6 = 6 - 4n - 6
Combine like terms
n + 4 n = 4 + 6
5n = 10
n = 10/5 = 2
<u>∴ n = 2</u>
Answer: 180
Multiples of 18: 18, 36, 54, 72, 90, 108, 126, 144, 162, 180
Multiples of 20: 20, 40, 60, 80, 100, 120, 140, 160, 180
F(x) = (x − 1)(x − 2)(x − 3)
Answer:
15000(1.003425)^12t ;
4.11%
4.188%
Step-by-step explanation:
Given that:
Loan amount = principal = $15000
Interest rate, r = 4.11% = 0.0411
n = number of times compounded per period, monthly = 12 (number of months in a year)
Total amount, F owed, after t years in college ;
F(t) = P(1 + r/n)^nt
F(t) = 15000(1 + 0.0411/12)^12t
F(t) = 15000(1.003425)^12t
2.) The annual percentage rate is the interest rate without compounding = 4.11%
3.)
The APY
APY = (1 + APR/n)^n - 1
APY = (1 + 0.0411/12)^12 - 1
APY = (1.003425)^12 - 1
APY = 1.04188 - 1
APY = 0.04188
APY = 0.04188 * 100% = 4.188%
