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3 years ago

What is an equation for the line that passes through points (8.-3) and (9, 10)?

Mathematics

1 answer:

harina [27]3 years ago

6 0

Answer:

y+3=13(x-8)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(10-(-3))/(9-8)

m=(10+3)/1

m=13/1

m=13

y-(-3)=13(x-8)

y+3=13(x-8)

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3 years ago

Slope intercept form of a line that has a slope of -3/4 and passes through (4, 3)

tia_tia [17]

<h3>Explanation</h3>

First Method

We have the given slope value and the coordinate point that the graph passes through.

$y = mx + b$

where m = slope and b = y-intercept. Substitute the value of slope in the equation.

$y = - \frac{3}{4} x + b$

We have the given coordinate point as well. After we substitute the slope, we substitute the coordinate point value in the equation.

$3 = - \frac{3}{4} (4) + b \\$

Solve the equation for b-term

$3 = - 3 + b \\ 3 + 3 = b \\ 6 = b$

The value of b is 6. We substitute the value of b in the equation.

$y = - \frac{3}{4} x + 6$

Second Method

We can also use the Point-Slope form to solve the question.

$y - y_1 = m(x - x_1)$

Given the y1 and x1 = the coordinate point value.

Substitute the slope and coordinate point value in the point slope form.

$y - 3 = - \frac{3}{4} (x - 4)$

Simplify/Convert into Slope-intercept

$y = - \frac{3}{4} (x - 4) + 3 \\ y = - \frac{3}{4} x + \frac{12}{4} + 3 \\ y = - \frac{3}{4} x + 3 + 3 \\y = - \frac{3}{4} x + 6$

<h3>Answer</h3>

 $\large \boxed {y = - \frac{3}{4} x + 6}$ 

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2 years ago

The slope that passes through the point (-2,-4) and (-3,-8) is

enot [183]

Answer:

$y=4x+b$ (four being the slope)

Step-by-step explanation:

So lets use

ΔY/ΔX

or the y2-y1 over x2-x1

$\frac{-8+4}{-3+2}$

$\frac{-4}{-1}$

Therefore, the slope is 4

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Answer:

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Step-by-step explanation:

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3 years ago

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