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3 years ago

7

the sum of Julio's and Charles's age is 44 years. seven year from now, Julio will be twice Charles's age. how old is each one no

w?

2 answers:

Natalka [10]3 years ago

4 0

Julio's age + Charles' age = 44
Julio's age + 7 = Charles' age times 2

Wewaii [24]3 years ago

3 0

J + C = 44

J + 7 = 2C

I hope this helps. :)

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Jeff has some coins so he can put in 6 bags or 9 bags with no coins left but if put in 5 bags 2 coins left. So at least how many

sertanlavr [38]

Answer:

72

Step-by-step explanation:

Jeff can divide the coin evenly in 6 or 9 bags, so the number of coin should have 9 and 6 as the factor. The lowest common factor for 6 and 9 will be:

6= 2 x 3

9= 3^2

LCF= 2 x 3^2= 18

From here you need to find the common multiple of 18 that will have 2 remainder after divided by 5. When 18( divided by 5, it will left 3 as remainder.

Multiple of 3 that give 2 remainder after divided by 5 will be 3x4= 12. Then least coin Jeff should have will be: 4x18= 72

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3 years ago

CAN SOMEONE PLEASE HELP ME!! I NEED HELP WITH 6TH GRADE MATH!!!

balu736 [363]

That's the correct answer :) Good job!

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3 years ago

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Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$

The standard error is given by the following formula:

$SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$

And replacing we have:

$SE=\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=3.306$

Confidence interval

Now we have everything in order to replace into formula (1):

$-15.8-2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-23.437$

$-15.8+2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-8.163$

So on this case the 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

8 0

3 years ago

A car travel at an average speed of 68 miles per hour. How many miles does other travel in 3 hours and 15 mins

jeka57 [31]

3 hours and 15 minutes equals to 3,25 hours. Distance equals the product of the time by the speed which is 3,25x68=221.
A car traveling at 68 miles per hour travels 221 miles in three hours and 15 minutes.

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3 years ago

Simplify -6/3 divided by 2/-9

posledela

Answer:

9

Step-by-step explanation:

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2 years ago

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