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Masja [62]
3 years ago
6

Find DY divided by DX by implicit differentiation y=sinxy 

Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

Step-by-step explanation:

y = sin(xy)\\\frac{d}{dx}y=cos(xy)(\frac{d}{dx}(xy))\\  \frac{d}{dx}y = cos(xy)(y + x*\frac{d}{dx}y)\\ write \: \frac{d}{dx}y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = \frac{ycos(xy)}{1-xcos(xy)}

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alukav5142 [94]

Answer:

13

Step-by-step explanation:

12*12=144

5*5=25

\sqrt{169}  = 13

7 0
2 years ago
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How do i answer these? can somebody try to explain it ? maybe using a photo as well
Travka [436]

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3 0
2 years ago
Choose the function that represents the data in the table.
viva [34]

y = 2 {x}^{2}  - 3

\huge\underline\mathtt\colorbox{cyan}{Explanation thing:}

Using hit and trial, you van find it pretty easily-

  • Putting x=0, we get y=-3
  • Putting x=1, we get y=-1
  • Putting x=2, we get y=5

You can try it for yourself as well, for me, I couldn't find any other option appropriate.

4 0
2 years ago
Please help!
Gemiola [76]

The earning of the salesperson is an illustration of a linear function.

The possible functions in the two scenarios are: \mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

The function is given as:

\mathbf{I(s) = 0.1s + 2000}

When the base salary is increased, a possible function is:

\mathbf{I(s) = 0.1s + 2500}

This is so, because 2500 is greater than 2000

When the commission rate is decreased, a possible function is:

\mathbf{I(s) = 0.05s + 2000}\\

This is so, because 0.05 is less than 0.1

So, the possible functions in the two scenarios are:

\mathbf{I(s) = 0.1s + 2500} and \mathbf{I(s) = 0.05s + 2000}\\

See attachment for the graphs of both functions

Read more about linear equations at:

brainly.com/question/21981879

5 0
2 years ago
Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver
umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) x^{2} + y^{2} + 4\cdot x - 6\cdot y  - 36 = 0 Given

(ii) x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0 Commutative Property

(iii) (x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0 Modulative/Associative Property/Additive Inverse Existence

(iv) (x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0  Perfect Trinomial Square

(v) (x+2)^{2} +(y-3)^{2} = 4 + 9 + 36 Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) (x+2)^{2} + (y-3)^{2} = 49 Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

(x-h)^{2}+ (y-k)^{2} = r^{2}

Where r is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

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3 years ago
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