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Masja [62]
3 years ago
6

Find DY divided by DX by implicit differentiation y=sinxy 

Mathematics
1 answer:
amm18123 years ago
6 0

Answer:

Step-by-step explanation:

y = sin(xy)\\\frac{d}{dx}y=cos(xy)(\frac{d}{dx}(xy))\\  \frac{d}{dx}y = cos(xy)(y + x*\frac{d}{dx}y)\\ write \: \frac{d}{dx}y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = \frac{ycos(xy)}{1-xcos(xy)}

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Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE
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Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
3 years ago
Enter the solutions from least to greatest. (2x +4)(3x -2)=0
morpeh [17]

Answer:

From least to greatest: -2, 2/3

Step-by-step explanation:

Set each factor equal to 0 and solve

2x + 4 =0

2x = -4

x = -2

3x - 2 = 0

3x = 2

x = 2/3

The solutions are -2 and 2/3

7 0
3 years ago
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7 0
4 years ago
What is the difference between the 5th multiple of 7 and 3rd multiple of 2 ?
lesya692 [45]

Answer:

<h3>5th Multiple of 7 = 35</h3><h3>3rd Multiple of 2 = 6</h3><h2>The Difference</h2>

=> 35-6

<h2>=> 29</h2>
4 0
3 years ago
Explain the distance formula. Then use it to calculate the
Alex777 [14]

Answer:

dAB=10\ units

Step-by-step explanation:

we know that

The <u>distance formula</u> is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(1, 1) and B(7, −7)

Let

(x1,y1)=A(1, 1)

(x2,y2)=B(7, −7)

substitute the given values in the formula

dAB=\sqrt{(-7-1)^{2}+(7-1)^{2}}

dAB=\sqrt{(-8)^{2}+(6)^{2}}

dAB=\sqrt{64+36}

dAB=\sqrt{100}

dAB=10\ units

6 0
3 years ago
Read 2 more answers
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