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emmasim [6.3K]
3 years ago
15

Scientists estimate that about 14 million species exist, and only about 50% of them have been studied and named. About how many

species have been studying your name?
Mathematics
2 answers:
Margarita [4]3 years ago
6 0

Answer:

about 7 million

Step-by-step explanation:

50% of 14million

0.50*14000000

7000000

ra1l [238]3 years ago
5 0

Answer:

About 7 million

Step-by-step explanation: because half of 14 is 7 then add the million to it

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Solve for w: 2w<9+5w
sertanlavr [38]

Answer:

w > -3

Step-by-step explanation:

2w<9+5w

Subtract 5w from each side

2w-5w<9+5w-5w

-3w <9

Divide each side by -3 remembering to flip the inequality

-3w/-3 > 9/-3

w > -3

5 0
3 years ago
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John joined a fitness club that has a membership fee of $30 +25 per month. Mary’s club has a fee of 50 and charges 15 per month.
zmey [24]
Just solve until the answers are the same


25 times x plus 30 for John

15 times x plus 50 for Mary

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3 years ago
On the board, your teacher shows an example of finding the range.
Gnesinka [82]
The answer is C: the missing number is 25
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Consider the following number line:
Tatiana [17]
Point A - 1
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Point C - 1/3

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8 0
2 years ago
Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 4,000,000 and a mean
In-s [12.5K]

Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 19000, \sigma = \sqrt{4000000} = 2000

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{20179 - 19000}{2000}

Z = 0.59.

Z = 0.59 has a p-value of 0.7224.

1 - 0.7224 = 0.2776.

0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

6 0
2 years ago
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