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Vaselesa [24]
2 years ago
14

5) Establish the indentity (cot + tan ) sin = sec . Show each step to justify your conclusion.

Mathematics
1 answer:
katen-ka-za [31]2 years ago
3 0

Answer:

Step-by-step explanation:

Identities : -

cot = cos / sin

tan = sin / cos

( cot + tan ) sin = sec

LHS

= ( cot + tan ) sin

= ( ( cos / sin ) + ( sin / cos ) ) sin

= ( ( cos sin ) / sin ) + ( sin² / cos )

= cos + ( sin² / cos )

LCM = cos

= ( cos² / cos ) + ( sin² / cos )

= ( cos² + sin² ) / cos

Identity : -

cos² + sin² = 1

= 1 / cos

= sec

= RHS

Hence proved.

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ad-work [718]

The answer is y = -5.5x - 52.

First, let's find the slope of the line.

m = Δy/Δx

  • m = -8 - 3 / -8 - (-10)
  • m = -11 / -8 + 10
  • m = -11/2
  • m = -5.5

Now, substitute the slope and one of the given points in the point slope equation.

<u>y - y₁ = m (x - x₁)</u>

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schepotkina [342]

Answer:

18) Area= 5*5/2=25/2=12.5 unit ^2

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Step-by-step explanation:

18. A(-3,0)

B(1,-3)

C(4,1)

AB=V(-3-1)^2+(0+3)^2=V16+9=V25=5

AC=V(-3-4)^2+(0-1)^2=V49+1=V50=5V2

BC=V(1-4)^2+(-3-1)^2=V9+16=V25=5

so AB=BC=5

and AC^2=AB^2+BC^2

so trg ABC is an isosceles right  angle triangle (<B=90)

Area= 5*5/2=25/2=12.5 unit ^2

19. A(a,a)

B(-a,-a)

C(-V3a, V3a)

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AC=V(a+V3a)^2+(a-V3)^2=Va^2+2a^2V3+3a^2+a^2-2a^2V3+3a^2=V8a^2

BC=V(-a+V3a)^2+(-a-V3a)^2=V8a^2

so AB=AC=BC

Area=AB^2V3/4=8a^2*V3/4=2V3a^2

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2 years ago
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Answer:

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Step-by-step explanation:

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Hope this helps!

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