Question

Explain how System 1 becomes equivalent to System 2.

Answer 1

Answer:

$\left\{\begin{array}{ccc}(A+L)x+(B+M)y=C+N\\Ax+By=C\end{array}\right$

A.The first equation in System 2 is the sum of the equations in System 1. The second equation in System 2 is the first equation in System 1.

Step-by-step explanation:

$\underline{+\left\{\begin{array}{ccc}Ax+By=C\\Lx+My=N\end{array}\right}\qquad\text{add both sides of the equations}\\(Ax+Lx)+(By+My)=C+N\qquad\text{distributive}\\(A+L)x+(B+M)y=C+N$

Answer 2

The correct answer is A) The first equation in System 2 is the sum of the equations in System 1. The second equation in System 2 is the first equation in System 1.

pls mark me brainliest