All categories

3 years ago

Which number line best represents he solution to the inequality -18x +3 <48?

Mathematics

1 answer:

Tanzania [10]3 years ago

6 0

Answer: A

Step-by-step explanation:

Staar testtt

You might be interested in

15 points !!!! Diameter Radius Area Circumference of 84mm

SSSSS [86.1K]

Answer:

$lets \: \: \: find \: \: the \: \: radius \\ = 2\pi \: r \\ = 2\pi \: r = 84 \\ = \frac{2\pi \: r}{2\pi } = \frac{84}{2\pi} \\ = r = 13.37mm$

$lets \: \: \: find \: \: the \: \: \: area \\ = \pi {r}^{2} \\ = \pi \times {13.37}^{2} \\ = 561.55 {mm}^{2}$

$lets \: \: \: find \: \: \: the \: \: diameter \\ = d = 2r \\ = d = 2 \times 13.37 \\ = d = 26.74mm$

6 0

3 years ago

What do I do if I fail an online Course in HS

mario62 [17]

I really don’t know maybe you’ll have summer school that’s what we have to do if we fail an online course we have to go to summer school.

5 0

3 years ago

Sea World has 9 aquariums with small fish in them and the number of fish in each tank are shown below:45,10,48,19,36,25,63,14,37

zepelin [54]

Answer:

Step-by-step explanation:

Add all the numbers

Divide by 9

5 0

3 years ago

Select all quantities that are proportional to the diagonal length of a square.

horsena [70]

Answer:

B. Perimeter of a square and

C. Side length of a square

Step-by-step explanation:

if n= side length of square then

Area of square is $n^{2}$
Perimeter of a square is 4×n
diagonal length of a square is $\sqrt{2}$ × n

Thus,

Perimeter of square can be expressed as

$2\sqrt{2}$ ×diagonal length of a square

Side length of a square can be expressed as

$\frac{1}{\sqrt{2} }$ ×diagonal length of a square

but Area of square is

$\frac{1}{\sqrt{2} }$ ×n×diagonal length of a square

As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>

5 0

3 years ago

Tcecarenko [31]

So the x intercepts are going to be at the places where y = 0 so you can just read that off and get (-2,0) and (3,0). Hope this helps :)

5 0

3 years ago