Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and 
.
To find:
The 
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]
In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]
In triangle AOB,
Therefore, the measure of angle AOB is 120 degrees.
Answer:
The third option.
Step-by-step explanation:
Hence the 3rd option.
Answer:
Step-by-step explanation:
first, we need to find the slope
slope = (y2 - y1) / (x2 - x1)
(-2,1)...x1 = -2 and y1 = 1
(0,8)...x2 = 0 and y2 = 8
now sub
slope = (8 - 1) / (0- (-2) = 7/(0 + 2) = 7/2
point slope form : y - y1 = m(x - x1)
using point (-2,1)....x1 = -2 and y1 = 1
slope(m) = 7/2
now sub
y - 1 = 7/2(x - (-2) =
y - 1 = 7/2(x + 2) <==== here is one answer
y - y1 = m(x - x1)
using point (0,8)...x1 = 0 and y1 = 8
slope(m) = 7/2
now sub
y - 8 = 7/2(x - 0) <===== another possible answer
