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oee [108]
3 years ago
12

Superman wants to get as much Kinetic energy (KE) as he can when hitting a baseball. He asks you if he should use a slightly hea

vier bat or if he should swing twice as fast. Which would you recommend to Superman and why?
Mathematics
1 answer:
AysviL [449]3 years ago
8 0

Answer: Swing twice as fast

Explanation: If superman wants to get a lot of kinetic energy he should swing fast. Kinetic energy is the energy of motion/movement so that means the  more you do something fast the more KE you will get and if you do something twice as fast then you will gain more kinetic energy.

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How do you find deviation and standard deviation
AveGali [126]

Answer: The standard deviation formula may look confusing, but it will make sense after we break it down. ...

Step 1: Find the mean.

Step 2: For each data point, find the square of its distance to the mean.

Step 3: Sum the values from Step 2.

Step 4: Divide by the number of data points.

Step 5: Take the square root.

Step-by-step explanation:

6 0
3 years ago
Ms. Cisneros ordered 26 sandwiches for her students from Jimmy John's.
marissa [1.9K]

Answer:

142.96 dollars

Step-by-step explanation:

8 0
3 years ago
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What is the percent decrease when the balance in a bank account goes from $300 to $60?
Rzqust [24]
80% decrease. because 1% of 300 is 3 which you multiply 3*20 and which means 20 percent equals $60 the leftover percent is the decrease
5 0
4 years ago
Read 2 more answers
Darren wants to estimate the mean age in a population of trees. He'll sample nnn trees and build a 90\%90%90, percent confidence
Alchen [17]

Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0
2 years ago
WORTH A WHOLE LOTTA POINTS!
dangina [55]

Where did you get that A and B? I could answer if you were much more precise.

8 0
4 years ago
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