I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
Answer:
Step-by-step explanation:
Given the rate of filling is 
and the rate of emptying the pool is 
. The height of the pool at any time is:
#Substitute the value of g in the height equation to find the height of the pool:
#g=1
#g=2
#g=3
#g=4
Write a C program to compute Matrix Multiplication of two matrices. Use one dimensional array to store each matrix, where each row is stored after another. Hence, the size of the array will be a product of number of rows times number of columns of that matrix. Get number of row and column from user and use variable length array to initialize the size of the two matrices as well as the resultant matrix. Check whether the two matrices can be multiplied or not. Write a getMatrix() function to generate the array elements randomly. Write a printMatrix() function to print the 1D array elements in 2D Matrix format. Also, write another function product(), which multiplies the two matrices and stores in the resultant matrix. With SEED 5, the following output is generated.
Sample Output
Enter the rows and columns of Matrix A with space in between: 3 5
Enter the rows and columns of Matrix B with space in between: 5 4
Matrix A:
8 6 4 1 6
2 9 7 7 5
1 3 1 1 2
Matrix B:
9 5 4 5
9 9 8 1
4 4 3 5
2 6 2 1
4 5 2 4
Product AxB:
168 146 106 91
161 186 125 81
50 52 37 22
In conclusion, the answer is D; No, because they are not similar triangles.
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