Ask question

Ask question

All categories

3 years ago

6

Line AB goes through the points A (0, –4) and B (6, 2). Which equation represents line AB?

1 answer:

Contact [7]3 years ago

7 0

Answer:

The slope is 1/3.

Step-by-step explanation:

To solve this problem you had to use the slope of an equation represents the line.

Slope formula:

$\displaystyle \frac{Y_2-Y_1}{X_2-X_1}$

$\displaystyle \frac{2-4}{6-0}=\frac{-2}{6}=\frac{-2\div2}{6\div2}=\frac{-1}{3}=-\frac{1}{3}$

Therefore, the slope is 1/3, which is our answer.

Hope this helps!

You might be interested in

The diameter of a circular swimming pool is 8.5 m. What is the approximate circumference of the pool? Round to the nearest tenth

artcher [175]

<span>I think the answer to this equation is26.7</span> $x^{2}$ .

4 0

3 years ago

Please help me! I will mark brainliest!

Elenna [48]

Answer:

Your picture didn't load?

Step-by-step explanation:

3 0

3 years ago

Please help me quickly

hichkok12 [17]

Answer:

Convenience sampling

Step-by-step explanation:

5 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

Solve the system using elimination.

Molodets [167]

Answer:

(-1, 3)

Step-by-step explanation:

x - 5y = -16 [Equation 1]

-x + 3y = 10 [Equation 2]

<u>Adding both equations</u>

x - x - 5y + 3y = -16 + 10
-2y = -6
y = 3

x - 5(3) = -16
x - 15 = -16
x = -1

<u>Solution</u> : (-1, 3)

5 0

2 years ago

Read 2 more answers