All categories

2 years ago

What is 0.75 over 100 simplest form?

Mathematics

1 answer:

STALIN [3.7K]2 years ago

4 0

.0075 is simplest... or .0075/1 if it needs to be a fraction i guess

You might be interested in

Solve the equation x^3 + 2x^2 - 11x -12 = 0

vagabundo [1.1K]

Answer: there are 4 solutions

x = -2

x = -1/2 = -0.500

x =(3-√5)/2= 0.382

x =(3+√5)/2= 2.618

Step-by-step explanation:

4 0

2 years ago

An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,

butalik [34]

Answer:

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

$r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t$

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

$s=\sqrt{r_{A}^{2}+r_{B}^{2}}$

Rate of change of such distance can be found by the deriving the expression in terms of time:

$\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }$

Where $\frac{dr_{A}}{dt} = 500\,\frac{mi}{h}$ and $\frac{dr_{B}}{dt} = 550\,\frac{mi}{h}$ , respectively. Distances of each airliner at 2:30 PM are:

$r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi$

$r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi$

The rate of change is:

$\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }$

$\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}$

6 0

2 years ago

17. Factor x ^ 3 + 5x ^ 2 - 9x - 45 . A. (x - 5)(x ^ 2 + 9) b . (x - 5)(x - 3) * (x + 3) Factor By Groupin (x + 5)(x - 3) * (x +

jok3333 [9.3K]

Answer:

Step-by-step explanation:

Given

x³ + 5x² - 9x - 45 ( factor the first/second and third/fourth terms )

= x²(x + 5) - 9(x + 5) ← factor out (x + 5) from each term

= (x + 5)(x² - 9) ← factor as a difference of squares

= (x + 5)(x - 3)(x + 3)

3 0

3 years ago

A toy company intends to ship out its entire stock of 13,257 toy trucks and five times as many toy cars. If each box hold 109 to

Leviafan [203]

There are 730 total boxes. The last box has 108 toys.

7 0

2 years ago

What is 5.46÷ 0.25 (show ur work long divison)

Licemer1 [7]

5.46/0.25= 21.84 hope it helps

3 0

2 years ago