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Inga [223]
3 years ago
8

A triangle has two sides of length 9 and 6. What is the smallest possible whole-number length for the third side?

Mathematics
2 answers:
erica [24]3 years ago
8 0

Answer:

c=4

Step-by-step explanation:

a=9, b=6, c=?

|a-b|<c<|a+b| (Triangle inequality)

|9-6|<c<|9+6|

|3|<c<|15|

3<c<15

then c=4 (smallest possible)

natka813 [3]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Let the third side = x.

The sum of any two sides must be greater than the third side

9+6 > x

15 > x

9 + x > 6

x > 6-9

x > -3

6+ x > 9

x > 9-6

x > 3

So 3 < x < 15

Therefore the smallest whole number length the third side could have is 4.

The largest whole number length the third side could  have is 14.

I hope this was helpful, please mark as brainliest

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all you need to do is times the dinominator into 100 so 20x5=100 and now you have to multipy the same number that you multiplyed the first one by so 3x5=15 so the anwer would be 15/100 and to put that in a decimal you need to see the number on top witch is 15 so your real ANWSER IS   .15

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Find the distance between the pair of points: (6,−3) and (1,0
rosijanka [135]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\sqrt{34}

»»————- ★ ————-««  

Here’s why:

⸻⸻⸻⸻

\text{\underline{The distance formula is:}}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⸻⸻⸻⸻

\boxed{\text{Calculating the answer....}}\\\\d = \sqrt{(1-6)^2+(0-(-3))^2}\\--------------\\\rightarrow d = \sqrt{(-5)^2+(3)^2}\\\\\rightarrow d = \sqrt{(25+9)}\\\\\rightarrow d =\boxed{ \sqrt{34} }

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.

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Step-by-step explanation:

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