Answer:
Option 2 is correct.
Step-by-step explanation:
For right triangle
The pythagoras theorem should satisfy
The square of longest side should be equal to the sum of square of other two sides
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
Case1:
We have ![(2,3,\sqrt{10})](https://tex.z-dn.net/?f=%282%2C3%2C%5Csqrt%7B10%7D%29)
If we substitute in the formula
we get:
![10\neq9+2](https://tex.z-dn.net/?f=10%5Cneq9%2B2)
which does not satisfy the condition.
Case2:
We have ![(3,5,\sqrt{34})](https://tex.z-dn.net/?f=%283%2C5%2C%5Csqrt%7B34%7D%29)
If we substitute in the formula
we get:
34=25+9
which satisfies the condition.
Hence, option 2 is correct.