Let x be the length of a month on the other dimension. Since a year value is 365.242 days
We have 2 × 365.242 = 5 × x
It means that 5x = 730,484
and that x = 730,484 / 5 ≈ 146,1 days rounded to the decimal
This means that a month length in the other dimension is of roughly 146 days.. and If we assume that a month in the other dimension is of 30 days approximately, then one day length would be of 146,1 / 30 ≈ 4.87 days
We are given with the expression <span>tan2x / x</span> and asked to evaluate the expression to limit as theta approaches zero. In this case, we substitute first zero. The answer is zero over zero. This is indeterminate so we derive the terms accdg to L'hopital's rule. The derivative is 2 sec^2 2x/1. cos 2x is 1 so is sec^2 2x. Hence the answer is 2.
Step-by-step explanation:
There are <u>1000</u> milligrams in 1 gram.
There are <u>1000 </u>litres in 1 kiloliter.
A.) 3x^2-2x+1
If graphed, it is the only graph that goes above the x axis and touches the y axis at around that particular point.
